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max2010maxim [7]
3 years ago
5

Which graph is generated by this table of values? x –4 0 3 y 1 2 3

Mathematics
1 answer:
Nookie1986 [14]3 years ago
7 0

Answer: See the graph attached.

Step-by-step explanation:

1. To solve this exercise you must plot the points given in the table of the problem, which are shown below:

(-4,1), (0,2), (3,3)

2. You must plot the first value of each ordered pair on the x-axis.

3. You must plot the second value of each ordered pair on the y-axis.

4. Therefore, when you plot them, you obtain the graph shown attached.

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The answer will be 0 because zero cannot be divided by itself or any number
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Find a third degree polynomial function of the lowest degree that has the zeros below and whose leading coefficient is one.
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Zeros are the x-values that make the function zero.
0 = (x-0)(x- -4)(x-3)

f(x) = x(x+4)(x-3)
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What are the slope and the y-intercept of the linear function that is represented by the table? x y Negative three-fourths Negat
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The slope and the y-intercept of the function are: A. Slope = -2/5; y-intercept = -1/3.

<h3>How to Find Slope and Y-intercept of a Linear Function?</h3>

Slope (m) = change in y / change in x.

Using two pairs of points form the table value, (1/4, -13/30) and (2/3, -3/5)"

Slope (m) = (-13/30 - (-3/5))/(1/4 - 2/3)

Slope (m) = (-13/30 + 3/5))/(1/4 - 2/3)

Slope (m) = (1/6)/(-5/12)

Slope (m) = (1/6)(12/-5) = 12/-30

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Plug in m = -2/5 and (x, y) = (2/3, -3/5) into y = mx + b to find the y-intercept (b).

-3/5 = -2/5(2/3) + b

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Learn more about the slope and y-intercept on:

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Brainliest gets 22 points
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Step-by-step explanation:

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2 years ago
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Find the angles of a rhombus if the ratio of the angles that the diagonals form with a side is 6:9.
fomenos

Answer:

The measures of the angles of the rhombus are 72° , 108° , 72° , 108°

Step-by-step explanation:

* Lets revise the properties of the rhombus

- It has 4 equal sides

- Each two opposite angles are equal

- Each two adjacent angles are supplementary (their sum = 180°)

- The diagonals are perpendicular to each other

- The diagonals bisect the vertices angles (divide each vertex into two

 equal parts)

* Now lets solve the problem

- Let the name of the rhombus is ABCD

- The two diagonals are AC and BD

- Let the diagonals AC and BD make the angles BAC and ABD with

 side AB

∵ The diagonals of the rhombus bisect the vertex angles

∴ m∠BAC is half m∠A

∴ m∠ABD is half m∠B

- There is a ratio between the measures of the angles BAC and ABD

∵ m∠BAC : m∠ABD = 6 : 9

∵ m∠A + m∠B = 180° ⇒ consecutive angles

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∵ m∠BAC : m∠ABD : their sum

         6     :       9      : 15⇒(6 + 9)

          ?    :        ?      : 90° ⇒(the sum of the angles)

∴ m∠BAC = 6/15 × 90° = 36°

∴ m∠ABD = 9/15 × 90° = 54°

∵ m∠BAC is half m∠A

∴ m∠A = 36° × 2 = 72°

∵ m∠ABD is half m∠B

∴ m∠B = 54° × 2 = 108°

* The measures of the angles of the rhombus are 72° , 108° , 72° , 108°

4 0
2 years ago
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