If m∠1 = 3x, m∠3 = 2x + 20 and m∠5 = 30, what is the value of x?

Mathematics

1 answer:

iogann1982 [59]3 years ago

6 0

M∠2 = 180 - m∠1 = 180 - 3x [supplementary angles]

In a triangle, the three interior angles always add to 180° ⇒
m∠2 + m∠3 + m∠5 = 180 
180-3x + 2x+20 + 30 = 180
230 - x = 180
x = 230 - 180
x = 50

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There are two numbers
x1 = -0.25 + 0.9682i <<<< answer 1
x2 = - 0.25 - 0.9582i <<<< answer 2

I take it there are two such numbers.
Let one number = x
Let one number = y

x + y = -0.5
y = - 0.5 - x (1)
xy = 1 (2)

Put equation 1 into equation 2
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b = 0.5
c = 1

$\text{x = }\dfrac{ -0.5 \pm \sqrt{0.5^{2} - 4*1*1 } }{2*1}$

x = [-0.5 +/- sqrt(0.25 - 4)] / 2
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x = [-0.25 +/- 0.9682i

x1 = -0.25 + 0.9682 i
x2 = -0.25 - 0.9682 i

These two are conjugates. They will add as x1 + x2 = -0.25 - 0.25 = - 0.50.

The complex parts cancel out. Getting them to multiply to 1 will be a little more difficult. I'll do that under the check.

Check
(-0.25 - 0.9682i)(-0.25 + 0.9682i)
Use FOIL
F:-0.25 * -0.25 = 0.0625
O: -0.25*0.9682i
I: +0.25*0.9682i
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Notice
The two middle terms (labled "O" and "I" ) cancel out. They are of opposite signs.

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