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KengaRu [80]
3 years ago
7

Please help me solve the problem 3 \sqrt[5] 3\sqrt[100]

Mathematics
1 answer:
Advocard [28]3 years ago
6 0
<span>3 X squareroot (10 X 100) = 3X (10) X squareroot (10) = [ where the squareroot of 100 is 10] 30 X squareroot (10) = 30 X squareroot (2 X 5) = [where the squareroot of 2 is 1.414] 30 X (1.414) X squareroot (5) = 94.85</span>
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Lunna [17]
X = 47
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If UV=x+13 and RT=x-37, What is the value of x?
liberstina [14]

Answer:

x = 87

Step-by-step explanation:

the ratio SR / RV is equal the ratio ST / TU (both ratios are equal to 1), and the angle in the vertex S is the same for both triangles SUV and STR, so we can affirm that these triangles are similar (case S-A-S).

Then, we have that the ratio SR / SV is the same as RT / UV:

SR / SV = RT / UV = 1 / 2

RT * 2 = UV

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8 0
3 years ago
A sample of a radioactive substance decayed to 97% of its original amount after a year. (Round your answers to two decimal place
Andrej [43]

Answer:

a) The half life of the substance is 22.76 years.

b) 5.34 years for the sample to decay to 85% of its original amount

Step-by-step explanation:

The amount of the radioactive substance after t years is modeled by the following equation:

P(t) = P(0)(1-r)^{t}

In which P(0) is the initial amount and r is the decay rate.

A sample of a radioactive substance decayed to 97% of its original amount after a year.

This means that:

P(1) = 0.97P(0)

Then

P(t) = P(0)(1-r)^{t}

0.97P(0) = P(0)(1-r)^{0}

1 - r = 0.97

So

P(t) = P(0)(0.97t)^{t}

(a) What is the half-life of the substance?

This is t for which P(t) = 0.5P(0). So

P(t) = P(0)(0.97t)^{t}

0.5P(0) = P(0)(0.97t)^{t}

(0.97)^{t} = 0.5

\log{(0.97)^{t}} = \log{0.5}

t\log{0.97} = \log{0.5}

t = \frac{\log{0.5}}{\log{0.97}}

t = 22.76

The half life of the substance is 22.76 years.

(b) How long would it take the sample to decay to 85% of its original amount?

This is t for which P(t) = 0.85P(0). So

P(t) = P(0)(0.97t)^{t}

0.85P(0) = P(0)(0.97t)^{t}

(0.97)^{t} = 0.85

\log{(0.97)^{t}} = \log{0.85}

t\log{0.97} = \log{0.85}

t = \frac{\log{0.85}}{\log{0.97}}

t = 5.34

5.34 years for the sample to decay to 85% of its original amount

8 0
3 years ago
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Valentin [98]

Answer:

3(1) _3 (3_4)

3_3 (1)

3_3

0

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3 years ago
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