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RSB [31]
3 years ago
9

If you add the digits in a two-digit number and multiply the sum by 7, the you get the original number. If you reverse the digit

s in the two digit number, the new number is 18 more than he sum if it’s two digit. What is the original number?
42
24
64
46
36
Mathematics
1 answer:
Serga [27]3 years ago
7 0
Hello!

Since when you multiply the number by 7 you get the original number the number is a multiple of 7

The only number that is a multiple of 7 is 42

The answer is 42

Hope this helps!
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The sum of a rational number and an even integer is rational. A) Always True B) Sometimes True C) Usually True D) Never True
SOVA2 [1]
I think that the sum will always be a rational number
let's prove that


<span>any rational number can be represented as a/b where a and b are integers and b≠0

</span>and an integer is the counting numbers plus their negatives and 0
so like -4,-3,-2,-1,0,1,2,3,4....

<span>so, 2 rational numbers can be represented as

</span>a/b and c/d (where a,b,c,d are all integers and b≠0 and d≠0)

their sum is
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ad/bd+bc/bd=
(ad+bc)/bd

1. the numerator and denominator will be integers
2. that the denominator does not equal 0

alright
1.
we started with that they are all integers
ab+bc=?
if we multiply any 2 integers, we get an integer
<span>like 3*4=12 or -3*4=-12 or -3*-4=12, etc.
</span>even 0*4=0, that's an integer
the sum of any 2 integers is an integer
like 4+3=7, 3+(-4)=-1, 3+0=3, etc.
so we have established that the numerator is an integer

now the denominator
that is just a product of 2 integers so it is an integer


<span>2. we originally defined that b≠0 and d≠0 so we're good

</span>therefore, the sum of any 2 rational numbers will always be a rational number <span>is the correct answer.</span>
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3 years ago
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Answer:

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Step-by-step explanation:

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