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2 years ago

Please help me .............

Mathematics

2 answers:

borishaifa [10]2 years ago

8 0

Answer:

The first one.

Step-by-step explanation:

For something to be considered to be a graph, every x value must have 1 y value. It does not matter if y values are the same, but you MUST make sure there is ONLY ONE of each value. So for example the second one wouldn't be a function because -5 appears twice for the x values, but with different y values. This would mean when graphed, it would fail the vertical line test (if you put a vertical line anywhere on the graph you will only get one point).

Talja [164]2 years ago

5 0

Answer:

The first one

Step-by-step explanation:

because it is the only one that actually applies to the function

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The net worthw(t) of a company is growing at a rate of′(t) = 2000−121t2dollarsper year, wheretis in years since 1990.(a) If the

stiv31 [10]

Answer:

The worth of the company in 2000 is $56,000.

Step-by-step explanation:

The growth rate of the company is:

$f'(t)=2000-12t^{2}$

To determine the worth of the company in 2000, first compute the change in the net worth during the period 1990 (t = 0) to 2000 (t = 10) as follows:

$\int\limits^{10}_{0} {2000-12t^{2}} \, dt =\int\limits^{10}_{0} {2000} \, dt-12\int\limits^{10}_{0} {t^{2}} \, dt=2000 |t|^{10}_{0}-12|\frac{t^{3}}{3}|^{10}_{0}\\=(2000\times10)-(4\times10^{3})\\=20000-4000\\=16000$

The increase in the company's net worth from 1990 to 2000 is $16,000.

If the company's worth was $40,000 in 1990 then the worth of the company in 2000 is:

Worth in 2000 = Worth in 1990 + Net increase in company's worth

$=40000+16000\\=56000$

Thus, the worth of the company in 2000 is $56,000.

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3 years ago

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Step-by-step explanation:

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