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KonstantinChe [14]
3 years ago
15

Can someone help me??!

Mathematics
2 answers:
sasho [114]3 years ago
8 0

When you compare two functions f(x) and g(x), you're looking for a special input x^\ast such that

f(x^\ast)=g(x^\ast)

Since you have the table with some possible candidates for x^\ast, you simply have to choose the row that gives values for f(x) and g(x) that are as close as possible (the exact solution would give the same value for f(x) and g(x), so the approximate solution will give values for f(x) and g(x) that are close to each other).

In your table, the values for f(x) and g(x) are closer when x=-0.75

ohaa [14]3 years ago
5 0

Answer:

From the table an approximate root is -0.75.

Step-by-step explanation:

The values of the 2 sides of the equation are closest when x = -0.75. The exact root is between -0.75 and -1.

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matrenka [14]

A.

So for 1 hour you pay 10 dolars then for 3 you pay 30 then for 11 you pay 110 then for 20 you pay 200.

For B and C I dont Know sorry.

4 0
3 years ago
Use the distributive property to simplify. -1(2p – q + 5)
Studentka2010 [4]
D. -2p + q - 5 - you have to multiply, then distribute parentheses and apply plus or minus rules. 
8 0
3 years ago
Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)
Mashcka [7]
The cone equation gives

z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2

which means that the intersection of the cone and sphere occurs at

x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92

i.e. along the vertical cylinder of radius \dfrac3{\sqrt2} when z=\dfrac3{\sqrt2}.

We can parameterize the spherical cap in spherical coordinates by

\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle

where 0\le\theta\le2\pi and 0\le\varphi\le\dfrac\pi4, which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is \dfrac3{\sqrt2}. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4

Now the surface area of the cap is given by the surface integral,

\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du
=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du
=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}
=18\pi\left(1-\dfrac1{\sqrt2}\right)
=9(2-\sqrt2)\pi
3 0
3 years ago
A rectangular garden has a width that is 10 feet shorter than the length. Write and simplify an expression to represent the area
morpeh [17]

Answer:

x²-10x=area

Step-by-step explanation:

Area= length×width

Length: x

Width: x-10

Area= x(x-10)= x²-10x

I hope this helps...

:)

6 0
4 years ago
Simplify 7 − 5(3)2 ?
Anastaziya [24]
The answer is 7 - 7.5

you multiply 5 and 3 and get 15 then divide by 2
8 0
3 years ago
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