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faltersainse [42]
3 years ago
5

Solve the system -2y+5z=-3 y=-5x-4z-5 x=4z+4

Mathematics
1 answer:
kow [346]3 years ago
6 0
-2y + 5z = -3
y = -5x - 4z - 5
x = 4z + 4

-2(-5(4z + 4) - 4z - 5) + 5z = -3
-2(-20z - 20 - 4z - 5) + 5z = -3
-2(-20z - 4z - 20 - 5) + 5z = -3
                    -2(-24z - 25) = -3
                          48z + 50 = -3
                          <u>       - 50  - 50</u>
                                 <u>48z</u> = <u>-53</u>
                                  48      48
                                     z = -1⁵/₄₈
x = 4(-1⁵/₄₈) + 4
x = -4⁵/₁₂ + 4
x = ⁵/₁₂

y = -5(⁵/₁₂) - 4(-1⁵/₄₈) - 5
y = -2¹/₂ + 4⁵/₁₂ - 5
y = 1¹¹/₁₂ - 5
y = -3¹/₂

(x, y, z) = (⁵/₁₂, -3¹/₂, -1⁵/₄₈)
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3x + y = 6

y =  - 3x + 6

The coefficient of x is the slope of the line , So the slope of the above equation is -3 .

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Remember from now on ,

Product of multiplying the slopes of two lines which are perpendicular to each other , is -1 .

Thus ;

( - 3) \times (m) =  - 1

m is the slope of the line which we want.

- 3m =  - 1

Negatives simplifies

3m = 1

Divide sides by 3

\frac{3m}{3}  =  \frac{1}{3}  \\

m =  \frac{1}{3}  \\

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We have following equation to find the point-slope form of the linear functions :

y - y(0) = m(x - x(0))

x(0) and y(0) are the coordinates of the point which the line passed through.

y  - 8 =  \frac{1}{3} (x - 0) \\

y - 8 =  \frac{1}{3} x \\

Add sides 8

y =  \frac{1}{3} x + 8 \\

Done....

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Step-by-step explanation:

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Answer:

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Also given,

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a.)

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