<span>pH = pKa + log([A^-]/[HA])
[A^-] = [KF] = 0.43 M, [HA] = [HF] = 0.20 M
pKa = -logKa = -log(6.8x10^-4) = 3.17
pH = 3.17+ log(0.43 / 0.20) = 3.50
You can determine the [H3O^+] by using the equation for pH
pH = -log[H3O^+]
[H3O^+] = 10^-pH = 10^-3.50 = 3.16x10^-4 M</span>
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Answer:
3AgNO₃ (aq) + Na₃PO₄(aq) → Ag₃PO₄(s) ↓ + 3NaNO₃(aq)
Explanation:
The reaction is:
3AgNO₃ (aq) + Na₃PO₄(aq) → Ag₃PO₄(s) ↓ + 3NaNO₃(aq)
3 moles of silver nitrate and 1 mol of sodium phosphate, react in order to produce 1 mol of solid silver phosphate 3 moles of sodium nitrate
3Ag⁺(aq) + PO₄³⁻ (aq) → Ag₃PO₄(s) ↓
I not sure, but i know that is soft yellow no white not yellow.
Answer:
Electronegativity varies in a predictable way across the periodic table. Electronegativity increases from bottom to top in groups, and increases from left to right across periods. Thus, fluorine is the most electronegative element, while francium is one of the least electronegative.Explanation: