The distance between these coordinates is 13.41
Answer:
For t = 0.33 s, H = 14.0976 feet;
For t = 3 s, H = 0 feet;
For t = 16 s, H = -3328 feet;
For t = 48 s, H = -34560 feet.
Step-by-step explanation:
Assuming there's a typo on the problem and it wishes to determine the distance traveled by the ball in the given times instead of the time, we can solve it as shown below:
For t = 0.33 s:

For t = 3 s:

For t = 16 s:

For t = 48 s:

Answer:
![n = \frac{r}{\sqrt[nt]{\frac{a}{p}} -1 }](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7Br%7D%7B%5Csqrt%5Bnt%5D%7B%5Cfrac%7Ba%7D%7Bp%7D%7D%20-1%20%7D)
Step-by-step explanation:


![\sqrt[nt]{\frac{a}{p}} =(1+\frac{r}{n} )](https://tex.z-dn.net/?f=%5Csqrt%5Bnt%5D%7B%5Cfrac%7Ba%7D%7Bp%7D%7D%20%20%3D%281%2B%5Cfrac%7Br%7D%7Bn%7D%20%29)
![\sqrt[nt]{\frac{a}{p}} -1 =(\frac{r}{n} )](https://tex.z-dn.net/?f=%5Csqrt%5Bnt%5D%7B%5Cfrac%7Ba%7D%7Bp%7D%7D%20-1%20%3D%28%5Cfrac%7Br%7D%7Bn%7D%20%29)
![n = \frac{r}{\sqrt[nt]{\frac{a}{p}} -1 }](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7Br%7D%7B%5Csqrt%5Bnt%5D%7B%5Cfrac%7Ba%7D%7Bp%7D%7D%20-1%20%7D)
[ Do not confuse, as there are 2 n's, one in subject and another as power. We can never make the power or in a root, the subject. In order to solve for n, we have to make the character "n", the subject. ]