Answer:
r = 6
Step-by-step explanation:
V(cyl) = π · r² · h
144π = π · r² · 4
144 = r² · 4
<u>144</u> = r²
4
r = ÷
r = 12/2
r = 6
Well first you have to simplify the denominators with x, by multiplying the denominator on the left times the top and bottom of the middle, and vice versa to get 10x/(4x^2-4x)-9(2x-2)/(4x^2-4x)=-1/4 and then you combine the fractions on the left to get 2(9-4x)/(4x^2-4x)=-1/4 and then you cross multiply the fractions to get 8(9-4x)=-4x^2+4x and then simplify to get 72-32x=-4x^2+4x and then 4x^2-36x+72=0 which then we can turn into 4(x-6)(x-3)=0 so x is 6 and 3
Answer:
ASA and AAS
Step-by-step explanation:
We do not know if these are right triangles; therefore we cannot use HL to prove congruence.
We do not have 2 or 3 sides marked congruent; therefore we cannot use SSS or SAS to prove congruence.
We are given that EF is parallel to HJ. This makes EJ a transversal. This also means that ∠HJG and ∠GEF are alternate interior angles and are therefore congruent. We also know that ∠EGF and ∠HGJ are vertical angles and are congruent. This gives us two angles and a non-included side, which is the AAS congruence theorem.
Since EF and HJ are parallel and EJ is a transversal, ∠JHG and ∠EFG are alternate interior angles and are congruent. Again we have that ∠EGF and ∠HGJ are vertical angles and are congruent; this gives us two angles and an included side, which is the ASA congruence theorem.
1 way : 10d + 2d
another way: 5d + 5d + 2d
Number of solutions: no roots
Type of solution: Not Real
Step-by-step explanation:
We need to identify the number of solutions and their types using the discriminant.
We are given:
Rearranging:
Discriminant can be found by:
where b=-40, a=10 and c=41
Putting values:
So, Discriminant is -40
If the discriminant is less than zero i.e -40 then there are no real roots.
So, Number of solutions: no roots
Type of solution: Not Real
Keywords: discriminant
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