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3 years ago

7

Help anyone? dying

1 answer:

Oduvanchick [21]3 years ago

8 0

Answer: $\bold{f^{-1}(x)=\dfrac{2x-1}{2+x}}$

<u>Step-by-step explanation:</u>

Inverse is when you swap the x's and y's and then manipulate the equation to solve for y.

$y=\dfrac{2x+1}{2-x}\\\\\\\text{Swap the x's and y's:}\\x=\dfrac{2y+1}{2-y}\\\\\\\text{Multiply both sides by 2-y}:\\x(2-y)=2y+1\\\\\\\text{distribute x into 2-y}:\\2x-xy=2y+1\\\\\\\text{subtract 1 from both sides and add xy to both sides}:\\2x-1=2y+xy\\\\\\\text{factor out y from the right side}:\\2x-1=y(2+x)\\\\\\\text{divide 2+x from both sides}:\\\dfrac{2x-1}{2+x}=y\\\\\\\text{Therefore, the inverse }f^{-1}(x)=\dfrac{2x-1}{2+x}$

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Step-by-step explanation:

Given : Number of students : 11

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