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satela [25.4K]
3 years ago
6

Find the missing exponent.

Mathematics
2 answers:
Oduvanchick [21]3 years ago
8 0
1 would be the answre
erik [133]3 years ago
4 0

Answer:

1

Step-by-step explanation:

It is the most logical answer

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The coordinate grid shows points A through K. What point is a solution to the system of inequalities? y ≤ −2x + 10 y > 1 over
vlabodo [156]

Answer:

A, C, D and K

Step-by-step explanation:

First, plot the solution set to the system of two inequalities.

The inequality y\le -2x+10 determines solid line and bottom shaded region under this line.

The inequality y>\dfrac{1}{2}x-2 determines dotted line and top shaded region under this line.

The intersection of these two regions is the solution set to the system of two inequalities.

Points A, C, D and K belong to this region.

4 0
3 years ago
Sally designs web pages. She charges $140 per web page. She also needs to pay
dolphi86 [110]
You will take 140 times 5 since that is the amount she made so you times it buy the price she earns then after you do that subtract it buy 650 since that is what you have to pay
140 x 5 = 700
700 - 650 = 50
so she made a profit of 50
6 0
3 years ago
I need help um i dont need to to my work or check my answer just
romanna [79]
3.
area=legngth tiimes width
legnth is 10 more than 2 times width
l=10+2w
lw=area=(10+2w)w=10w+2w^2
area=3600
3600=10w+2w^2
so divide by 2
1800=5w+w^2
subtract 1800 from both sides
(note they used x instead of w)
0=w^2+5w-1800
then the facotred form is (w-40)(w+45)=0

0 product property measn if you have xy, then x and or y =0

therefor
w-40=0 and w+45=0
w=40 or -45
discard negative because negative legnth is not possible


explian how solution relates to situation
it is math so it is correct because we represented it corrrectly


the other solution is because of math and eliminate negative legnth becasue tha tis not possible
basically because we represented it correctly
not a very clear quetion to answer

basically 'because it represents the solution so we solved it and it is correct'


8 0
3 years ago
Read 2 more answers
Calculus Problem
Roman55 [17]

The two parabolas intersect for

8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2

and so the base of each solid is the set

B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, |x^2-(8-x^2)| = 2|x^2-4|. But since -2 ≤ x ≤ 2, this reduces to 2(x^2-4).

a. Square cross sections will contribute a volume of

\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x

where ∆x is the thickness of the section. Then the volume would be

\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x

We end up with the same integral as before except for the leading constant:

\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx

Using the result of part (a), the volume is

\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x

and using the result of part (a) again, the volume is

\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}

7 0
2 years ago
Construct the perpendicular bisector of the following segments.
lyudmila [28]

Answer:

what segments

Step-by-step explanation:

7 0
3 years ago
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