All categories

2 years ago

I need help can someone pls find the answer

Mathematics

1 answer:

dem82 [27]2 years ago

5 0

Answer:

4 is the answer

Step-by-step explanation:

because they gave 6into-4 =24

6into4 =24

I think it will help full for uu

it is helpful pls. do lijee

You might be interested in

At which points are the equations y = x- + 3x + 2 and y = 2x + 3 approximately equal?

jarptica [38.1K]

Select all the correct locations on the graph. At which points are the equations y = x2 + 3x + 2 and y = 2x + 3 approximately equal? 2.

4 0

1 year ago

Read 2 more answers

Obtain the general solution to the equation. (x^2+10) + xy = 4x=0 The general solution is y(x) = ignoring lost solutions, if any

alukav5142 [94]

Answer:

$y(x)=4+\frac{C}{\sqrt{x^2+10}}$

Step-by-step explanation:

We are given that a differential equation

$(x^2+10)y'+xy-4x=0$

We have to find the general solution of given differential equation

$y'+\frac{x}{x^2+10}y-\frac{4x}{x^2+10}=0$

$y'+\frac{x}{x^2+10}y=4\frac{x}{x^2+10}$

Compare with

$y'+P(x) y=Q(x)$

We get

$P(x)=\frac{x}{x^2+10}$

$Q(x)=\frac{4x}{x^2+10}$

I.F= $e^{\int\frac{x}{x^2+10} dx}=e^{\frac{1}{2}ln(x^2+10)}$

$e^{ln\sqrt(x^2+10)}=\sqrt{x^2+10}$

$y\cdot \sqrt{x^2+10}=\int \frac{4x}{x^2+10}\times \sqrt{x^2+10} dx+C$

$y\cdot \sqrt{x^2+10}=\int \frac{4x}{\sqrt{x^2+10}}+C$

$y\cdot \sqrt{x^2+10}=4\sqrt{x^2+10}+C$

$y(x)=4+\frac{C}{\sqrt{x^2+10}}$

6 0

2 years ago

Please help!! 15 points

zlopas [31]

Answer:

? = 125°

Step-by-step explanation:

The central angle is equal to the measure of the arc that subtends it, thus

? = 125°

3 0

2 years ago

Please help with A.

Furkat [3]

Answer:

ok so I dont have the answer but I suggest if u can u do the tutor they help a lot u can only ask 1 question per session but trust me it's helpful

they also say the answer at the end

so first they explain how to get the answer like they do the math

3 0

2 years ago

Steven has 14 steel balls of equal weight. If he puts 9 of them in one pan of a pan balance and the rest along with a weight of

nikklg [1K]

Answer:

answer os 5 grams

Step-by-step explanation:

i took the test

7 0

2 years ago