Answer:
a microhabitat is a habitat which is of small or limited extent .
Explanation:
Answer:
The correct statements are :b, c , d, and e.
Explanation:
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as 
K is the constant of a certain reaction when it is in equilibrium, while Q is the equilibrium quotient of activities of products and reactants at any stage other than equilibrium of a reaction.
, reaction will move in forward direction and concentration of products will increase.
, reaction will move in backward direction and concentration of reactant will increase.
reaction is at equilibrium.
The given function is:
P = 120 i / (i^2 + i + 9)
or
P = 120 i (i^2 + i + 9)^-1
<span>The maxima point is obtained by taking the 1st
derivative of the function then equating dP / di = 0:</span>
dP / di = 120 (i^2
+ i + 9)^-1 + (-1) 120 i (i^2 + i + 9)^-2 (2i + 1)
setting dP / di =0 and multiplying whole equation by (i^2
+ i + 9)^2:
0 = 120 (i^2 + i + 9) – 120i (2i + 1)
Dividing further by 120 will yield:
i^2 + i + 9 – 2i^2 – i = 0
-i^2 + 9 =0
i^2 = 9
<span>i = 3 (ANSWER)</span>
Therefore P is a maximum when i = 3
Checking:
P = 120 * 3 / (3^2 + 3 + 9)
P = 17.14
Answer:
pH = 2.46
Explanation:
Hello there!
In this case, since this neutralization reaction may be assumed to occur in a 1:1 mole ratio between the base and the strong acid, it is possible to write the following moles and volume-concentrations relationship for the equivalence point:

Whereas the moles of the salt are computed as shown below:

So we can divide those moles by the total volume (0.021L+0.0066L=0.0276L) to obtain the concentration of the final salt:
![[salt]=0.01428mol/0.0276L=0.517M](https://tex.z-dn.net/?f=%5Bsalt%5D%3D0.01428mol%2F0.0276L%3D0.517M)
Now, we need to keep in mind that this is an acidic salt since the base is weak and the acid strong, so the determinant ionization is:

Whose equilibrium expression is:
![Ka=\frac{[C_6H_5NH_2][H_3O^+]}{C_6H_5NH_3^+}](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BC_6H_5NH_2%5D%5BH_3O%5E%2B%5D%7D%7BC_6H_5NH_3%5E%2B%7D)
Now, since the Kb of C6H5NH2 is 4.3 x 10^-10, its Ka is 2.326x10^-5 (Kw/Kb), we can also write:

Whereas x is:

Which also equals the concentration of hydrogen ions; therefore, the pH at the equivalence point is:

Regards!