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harina [27]
3 years ago
9

What is the mass of a mole of lithium oxide?

Chemistry
1 answer:
liubo4ka [24]3 years ago
6 0
It might be 29.88
sry I couldn't be of much help.
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Pls help ASAP I DONT have time IT ALSO DETECTS IF ITS RIGHT OR WRONGG ......just answer the bottom one not the top plss
Iteru [2.4K]

Answer:

a microhabitat is a habitat which is of small or limited extent .

Explanation:

3 0
3 years ago
For the reaction: P4 + 6C12 – 4 PC13
bagirrra123 [75]

Answer:

332.3g

Explanation:

hope this helps loves x

5 0
3 years ago
Which of the following statements about the reaction quotient, Q is false? a. The value of Q can be used to predict equilibrium
irakobra [83]

Answer:

The correct statements are :b, c , d, and e.

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{eq}

K is the constant of a certain reaction when it is in equilibrium, while Q is the equilibrium quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

  • Q_c, reaction will move in forward direction and concentration of products will increase.
  • Q_c>K_c, reaction will move in backward direction and concentration of reactant will increase.
  • Q_c=K_c reaction is at equilibrium.

4 0
3 years ago
The rate (in mg carbon/m3/h) at which photosynthesis takes place for a species of phytoplankton is modeled by the function p = 1
maxonik [38]

The given function is:

P = 120 i / (i^2 + i + 9)

or

P = 120 i (i^2 + i + 9)^-1

<span>The maxima point is obtained by taking the 1st derivative of the function then equating dP / di = 0:</span>

dP / di = 120 (i^2 + i + 9)^-1 + (-1) 120 i (i^2 + i + 9)^-2 (2i + 1)

setting dP / di =0 and multiplying whole equation by (i^2 + i + 9)^2:

0 = 120 (i^2 + i + 9) – 120i (2i + 1)

Dividing further by 120 will yield:

i^2 + i + 9 – 2i^2 – i = 0

-i^2 + 9 =0

i^2 = 9

<span>i = 3      (ANSWER)</span>

Therefore P is a maximum when i = 3

Checking:

P = 120 * 3 / (3^2 + 3 + 9)

P = 17.14

8 0
3 years ago
If 21.00 mL of a 0.68 M solution of C6H5NH2 required 6.60 mL of the strong acid to completely neutralize the solution, what was
Andru [333]

Answer:

pH = 2.46

Explanation:

Hello there!

In this case, since this neutralization reaction may be assumed to occur in a 1:1 mole ratio between the base and the strong acid, it is possible to write the following moles and volume-concentrations relationship for the equivalence point:

n_{acid}=n_{base}=n_{salt}

Whereas the moles of the salt are computed as shown below:

n_{salt}=0.021L*0.68mol/L=0.01428mol

So we can divide those moles by the total volume (0.021L+0.0066L=0.0276L) to obtain the concentration of the final salt:

[salt]=0.01428mol/0.0276L=0.517M

Now, we need to keep in mind that this is an acidic salt since the base is weak and the acid strong, so the determinant ionization is:

C_6H_5NH_3^++H_2O\rightleftharpoons  C_6H_5NH_2+H_3O^+

Whose equilibrium expression is:

Ka=\frac{[C_6H_5NH_2][H_3O^+]}{C_6H_5NH_3^+}

Now, since the Kb of C6H5NH2 is 4.3 x 10^-10, its Ka is 2.326x10^-5 (Kw/Kb), we can also write:

2.326x10^{-5}=\frac{x^2}{0.517M}

Whereas x is:

x=\sqrt{0.517*2.326x10^{-5}}\\\\x=3.47x10^-3

Which also equals the concentration of hydrogen ions; therefore, the pH at the equivalence point is:

pH=-log(3.47x10^{-3})\\\\pH=2.46

Regards!

6 0
3 years ago
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