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zhenek [66]
3 years ago
8

How to figure out which melting point would have the lowest melting point ?

Chemistry
2 answers:
77julia77 [94]3 years ago
8 0

Answer:

By evaluating the intermolecular forces and size!

Explanation:

Essentially the stronger the forces the higher the melting point... Here is a list of interemolecular forces (the first will be the weakest).

1) Dispersion forces (Exhibited by evrey molecule) (Weakest)

2) Dipole-Dipole

3) Hydrogen bonding

4) Ionic bonds (Strongest)

The stronger the forces it has then the higher the melting point. Also aromatic structures have a higher melting point as well. A general rule of thumb is, the larger the structure is then the higher thee melting point it.

stellarik [79]3 years ago
6 0

Answer:

That would be helium, with a melting point of 0.95 K (-272.20 °C)—although this happens only under considerable pressure (~25 atmospheres). At ordinary pressure, helium would remain liquid even if it could be chilled to absolute zero.

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krek1111 [17]

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<h3>What is Function Group ?</h3>

In organic chemistry, a functional group is a collection of atoms within molecules that interact to cause predictable reactions. Functional groups include the hydroxyl, ketone, amine, and ether groups, for instance.

(b) Most double bonds, such those found in alkenes, are formed when two carbon atoms are present. In a carbonyl group, for instance, where a carbon atom and an oxygen atom are together, there are several double bonds connecting the two separate components. Sulfoxides (S=O), imines (C=N), and azo compounds (N=N) also include common double bonds.

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8 0
1 year ago
In a titration of 0.35 M HCl and 0.35 M NaOH, how much NaOH should be added to 45.0 ml of HCl to completely neutralize the acid?
Bezzdna [24]
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Firstly, here is your formula: M(HCI) x V(HCI) = M(NaOh) x V(NaOH) 
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6 0
3 years ago
A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f
Allisa [31]

Answer:

The mass of water m_{w} = 39.18 gm

Explanation:

Mass of iron m_{iron} = 32.5 gm

Initial temperature of iron T_{1} = 22.4°c = 295.4 K

Specific heat of iron  C_{iron} = 0.448 \frac{KJ}{kg K}

Mass of water = m_{w}

Specific heat of water  C_{w} = 4.2 \frac{KJ}{kg  K}

Initial temperature of water T_{2} = 336 K  

Final temperature after equilibrium T_{f} = 59.7°c = 332.7 K

When iron rod is submerged into water then

Heat lost by water  = Heat gain by iron rod

m_{w} C_{w} (T_{2} - T_{f} ) =  m_{iron} C_{iron} ( T_{f} - T_{1} )

Put all the values in above formula we get

m_{w} × 4.2 × ( 336 - 332.7 ) = 32.5 × 0.448 × ( 332.7 - 295.4 )

m_{w} = 39.18 gm

Therefore the mass of water m_{w} = 39.18 gm

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