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Nata [24]
2 years ago
8

Study the diagram of radioactive decay. Which option identifies what the arrows in the diagram represent? atoms and elements ele

ments and gas energy and particles gas and atoms.
Chemistry
2 answers:
zvonat [6]2 years ago
8 0

Energy and particles are produced from the radioactive decay.

By studying the diagram of radioactive decay we identifies two materials i.e. energy and particles which are the two products emitting from the radioactive source.

From radioactive decay, radiation is emitting in the form of alpha, beta and gamma radiation as well as the production of particle that is stable without radiation so we can conclude that energy and particles are the two products produced from the process of radioactive decay.

Learn more: brainly.com/question/25802672

Lena [83]2 years ago
4 0

The arrows in the image represent energy and particles.

Radioactive decay involves the disintegration of a nucleus to yield smaller nuclei with the emission of energy. The process may occur spontaneously for large nuclei or it may be induced by bombardment with other particles.

We know that radioactive decay leads to;

  • Formation of new nucleus/nuclei
  • Emission of energy
  • Emission of particles

Therefore, the arrows in the image represent energy and particles.

Learn more: brainly.com/question/17638582

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Which property of a body cannot be changed if a force is applied to it?
prohojiy [21]
The answer is it’s mass
8 0
3 years ago
Read 2 more answers
29.47 mL of a solution of the acid HBr is titrated, and 72.90 mL of 0.2500-M NaOH is required to reach the equivalence point. Ca
Klio2033 [76]

The original concentration of the acid solution is 6.175 \times 10^-4 mol / L.

<u>Explanation:</u>

Concentration is the ratio of solute in a solution to either solvent or total solution. It is expressed in terms of mass per unit volume

                        HBr + NaOH -----> NaBr + H2O

There is a 1:1 equivalence with acid and base.

Moles of NaOH = 72.90 \times 10^-3 \times 0.25

                          = 0.0182 mol.

[ HBr ] = moles of base / volume of a solution

          = 0.0182 / 29.47

          = 6.175 \times 10^-4 mol / L.

4 0
3 years ago
Calculate the solubility at 25°C of CuBr in pure water and in a 0.0120M CoBr2 solution. You'll find Ksp data in the ALEKS Data t
iragen [17]

Answer:

S = 7.9 × 10⁻⁵ M

S' = 2.6 × 10⁻⁷ M

Explanation:

To calculate the solubility of CuBr in pure water (S) we will use an ICE Chart. We identify 3 stages (Initial-Change-Equilibrium) and complete each row with the concentration or change in concentration. Let's consider the solution of CuBr.

    CuBr(s) ⇄ Cu⁺(aq) + Br⁻(aq)

I                       0             0

C                     +S           +S

E                       S             S

The solubility product (Ksp) is:

Ksp = 6.27 × 10⁻⁹ = [Cu⁺].[Br⁻] = S²

S = 7.9 × 10⁻⁵ M

<u>Solubility in 0.0120 M CoBr₂ (S')</u>

First, we will consider the ionization of CoBr₂, a strong electrolyte.

CoBr₂(aq) → Co²⁺(aq) + 2 Br⁻(aq)

1 mole of CoBr₂ produces 2 moles of Br⁻. Then, the concentration of Br⁻ will be 2 × 0.0120 M = 0.0240 M.

Then,

    CuBr(s) ⇄ Cu⁺(aq) + Br⁻(aq)

I                       0           0.0240

C                     +S'           +S'

E                       S'            0.0240 + S'

Ksp = 6.27 × 10⁻⁹ = [Cu⁺].[Br⁻] = S' . (0.0240 + S')

In the term (0.0240 + S'), S' is very small so we can neglect it to simplify the calculations.

S' = 2.6 × 10⁻⁷ M

8 0
3 years ago
What is the charge of a cation?
kolezko [41]

Answer:

A cation has more protons than electrons, consequently giving it a net positive charge. For a cation to form, one or more electrons must be lost, typically pulled away by atoms with a stronger affinity for them.

Were i found my answer: Cation vs Anion: Definition, Chart and the Periodic Table

Explanation:

5 0
3 years ago
Giúp mình 2 câu này với ạ
alisha [4.7K]

Answer:it is wrong answer

Explanation:estro man

5 0
2 years ago
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