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Nata [24]
2 years ago
8

Study the diagram of radioactive decay. Which option identifies what the arrows in the diagram represent? atoms and elements ele

ments and gas energy and particles gas and atoms.
Chemistry
2 answers:
zvonat [6]2 years ago
8 0

Energy and particles are produced from the radioactive decay.

By studying the diagram of radioactive decay we identifies two materials i.e. energy and particles which are the two products emitting from the radioactive source.

From radioactive decay, radiation is emitting in the form of alpha, beta and gamma radiation as well as the production of particle that is stable without radiation so we can conclude that energy and particles are the two products produced from the process of radioactive decay.

Learn more: brainly.com/question/25802672

Lena [83]2 years ago
4 0

The arrows in the image represent energy and particles.

Radioactive decay involves the disintegration of a nucleus to yield smaller nuclei with the emission of energy. The process may occur spontaneously for large nuclei or it may be induced by bombardment with other particles.

We know that radioactive decay leads to;

  • Formation of new nucleus/nuclei
  • Emission of energy
  • Emission of particles

Therefore, the arrows in the image represent energy and particles.

Learn more: brainly.com/question/17638582

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If the reaction N2 (g) + 3 H2 (g) --&gt; 2 NH3 (g) has the concentrations 1.1 M for nitrogen, 0.75 M for hydrogen and 0.25 M fo
Luba_88 [7]

<u>Answer:</u> The value of K_c is 0.136 and is reactant favored.

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For the chemical reaction between carbon monoxide and hydrogen follows the equation:

N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

The expression for the K_{c} is given as:

K_{c}=\frac{[NH_3]^2}{[N_2][H_2]^3}

We are given:

[NH_3]=0.25M

[H_2]=0.75M

[N_2]=1.1M

Putting values in above equation, we get:

K_c=\frac{(0.25)^2}{1.1\times (0.75)^3}

K_c=0.135

There are 3 conditions:

  • When K_{c}>1; the reaction is product favored.
  • When K_{c}; the reaction is reactant favored.
  • When K_{c}=1; the reaction is in equilibrium.

For the given reaction, the value of K_c is less than 1. Thus, the reaction is reactant favored.

Hence, the value of K_c is 0.136 and is reactant favored.

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3 years ago
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