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3 years ago

PLEASE HELP

1 answer:

5 0

1.D. 34 & 36
2.6
3.consecutive even integers are two numbers apartx = 1st even integerx+2 = next consecutive even integerx+(x+2)=462x+2=462x=44x=22so the two consecutive even integers are 22 and 24

4.Let's say that one of the consecutive even integers is n. That means that the next two are (n + 2) and (n + 4), for simplicity's sake. You can also say that the other two are (n - 2) and (n - 4) or that they are (n - 2) and (n + 2), but they would all give you the same numbers in the end. So if three consecutive even integers add up to 198: n + (n + 2) + (n + 4) = 198 We can solve for n: 3n + 6 = 198 3n = 192 n = 64 The other two integers are then (n + 2) = 66 and (n + 4) = 68.

5.It would be the 3rd option n + n+1 + n+2 + n+3 = 866.The perimeter is length + width + opposite length + opposite width, or in other words: 150 = 2L + 2W
<span>Also L = W + 15 </span>

<span>So, 150 = 2(W + 15) + 2W = 4W + 30 </span>

<span>This means, 4W = 120 or W = 30 </span>
<span>Therefore: L = 30 + 15 = 45
7.</span>Let the price be p. Then 1.10p = $8.25. Solving for p, p = $750 (answer)
8.C
I hope this helped!

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