If tan theta is -1, we know immediately that theta is in either Quadrant II or Q IV. We need to focus on Q IV due to the restrictions on theta.
Because tan theta is -1, the ray representing theta makes a 45 degree angle with the horiz axis, and a 45 degree angle with the negative vert. axis. Thus the hypotenuse, by the Pythagorean Theorem, tells us that the hyp is sqrt(2).
Thus, the cosine of theta is adj / hyp, or +1 / sqrt(2), or [sqrt(2)]/2
The secant of theta is the reciprocal of that, and thus is
2 sqrt(2)
---------- * ------------ = sqrt(2) (answer)
sqrt(2) sqrt(2)
-0.72 because u can’t write a check and u don’t have the funds
Answer:
<em>Pool 1 leaks faster than pool 2.</em>
Step-by-step explanation:
<u>Rates of change</u>
The rate of change (ROC) is a measure that compares two quantities, usually to know how fast one variable changes in time.
We are given two rates of change for two pools that are leaking. The first one loses 2/3 gallon in 15 minutes, and the other loses 3/4 gallon in 20 minutes.
To compare them, we are required to express time in hours. Recall one hour has 60 minutes, or equivalently, one minute has 1/60 hours. Converting both times, we have:
15 minutes = 15/60 = 1/4 hours
20 minutes = 20/60 = 1/3 hours
Now compute both rates of change:
Pool 1:

Pool 2:

Comparing both ratios, it's clear pool 1 leaks faster than pool 2.
9514 1404 393
Answer:
A. x² -4
B. 2x² +8
Step-by-step explanation:
The area of a square is the square of the side lengths. That means the area of each large square is x², since it has a side length of x.
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A. The area of 4 small squares is subtracted from the area of the large square to find the shaded area:
x² -4×1² = x² -4 . . . area of Figure A
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B. The area of two small squares is added to the area of two large squares to find the shaded area:
2x² +2×2² = 2x² +8 . . . area of Figure B
Answer:
Step-by-step explanation:
4x - 12 ≤ 16 + 8x
4x - 8x ≤ 16 + 12
- 4x ≤ 28
<em>x ≥ - 7 or [ - 7, ∞ )</em>