Can you help me with 4, 5, 6?I don't even know if number 4 is right.
1 answer:
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Answer:
Kyle filled 4 10-oz cups, 6 14-oz cups, and 4 20-oz cups.
Step-by-step explanation:
Let 10-oz, 14-oz, and 20-oz coffees be represented by the variables <em>a, b</em>, and <em>c</em>, respectively.
Since a total of 14 cups of coffee was served:
A total of 204 ounces of coffee was served. Therefore:
A total of $16.70 was collected. Hence:
This yields a triple system of equations. In order to solve a triple system, we should isolate the system to only two variables first.
From the first equation, let's subtract <em>a</em> and <em>b</em> from both sides:
Substitute this into both the second and third equations:
And:
In this way, we've successfully created a system of two equations, which can be more easily solved. Distribute:
For the Second Equation:
And for the Third:
We can solve this using substitution. From the second equation, isolate <em>a: </em>
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Substitute into the third:
Distribute and simplify:
Therefore:
Using the equation for <em>a: </em>
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And using the equation for <em>c: </em>
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Therefore, Kyle filled 4 10-oz cups, 6 14-oz cups, and 4 20-oz cups.
Answer:
The final price is $66.
Step-by-step explanation:
This question can be solved by a rule of three.
The initial price was of $120.
Initially, there was a discount of 15%. Then, there is another discount on the initial price. So the total discount is of 15+30 = 45%.
So the final price will be 100-45 = 55% = 0.55 of the initial price.
So
$120 - 1
x - 0.55
The final price is $66.