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3 years ago

(N + 1 )^ 2 for N = -9

Mathematics

1 answer:

Mariulka [41]3 years ago

3 0

Answer: 82

Step-by-step explanation:

(N + 1 )^ 2 for N = -9

(-9 +1))^ 2

81+1

(-9 +1))^ 2 - Every number raised to power 2 positive your result will be positive

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3 years ago

Our current equation is:

inessss [21]

Answer:

Step-by-step explanation:

subtracting 289 from both sides, will make one side will be equal to zero.

thus we can then easily solve for b.

can this answer get the brainliest tag?

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3 years ago

You have 88 grams of a radioactive kind of actinium. How much will be left after 44 years if its half-life is 22 years?

mash [69]

Answer:

22 grams

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3 0

3 years ago

Please help very urgent

Alik [6]

Answer:

32, 16, 8, 4, 2, 1

Explanation:

The geometric mean can be represented by $\sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}$ .

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

$a_{n} = a_{1} • r^{n-1}$

Where $a_{n}$ is the nth term, $a_{1}$ is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, $a_{1}$ will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

$\sqrt[5]{\frac{a_{6}}{a_{1}}}$ =

$\sqrt[5]{\frac{1}{32}}$ =

$\frac{1}{2}$ .

Therefore: $r = \frac{1}{2}$ .

Using all the information we have, we can find the explicit rule:

$a_{n} = a_{1} • r^{n-1}$

$a_{1}$ = 32
$r = \frac{1}{2}$

$a_{n} = a_{1} • r^{n-1}$ →

$\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}$

________________________________

We can test that this works by substituting the number location of the term you want to find.

For instance:

$a_{1} = 32 • (\frac{1}{2})^{1-1}$

$a_{1} = 32 • (\frac{1}{2})^{0}$

$a_{1} = 32 • 1$

$a_{1} = 32$

$a_{6} = 32 • (\frac{1}{2})^{6-1}$

$a_{6} = 32 • (\frac{1}{2})^{5}$

$a_{6} = 32 • \frac{1}{32}$

$a_{6} = 1$

3 0

3 years ago

Read 2 more answers

(-7/8)(-3/4) A:6/7 B:-21/32 C:21/32

Alekssandra [29.7K]

The answer is C
I pretty sure

7 0

3 years ago

Read 2 more answers