Answer:
2 stickers will be left over
Step-by-step explanation:
To answer the question, all you need to do is figure out at what value of stickers would the remaining stickers be equal to 2 if the piles are made up of either 3 to a set or 4 to a set. To do this, we need to figure out the size of the whole set of stickers.
Lets assume that the total number of stickers is 14. Lets test the 2 given conditions. If we divide it in piles of 3 then we will have a pile of 12 stickers (4 piles of 3 stickers each) with 2 stickers remaining.
Lets test the second condition. If we divide it in piles of 4, we will again have 12 stickers (3 piles of 4 stickers each) with 2 stickers remaining.
Now that both conditions have been satisfied, all we have to do is see how many stickers are left if we make a pile of 12 stickers. In this case, we will have just one pile of 12 stickers and, again, we will be left with 2 stickers.
Therefore, the answer is 2 stickers
Answer:4.5
Step-by-step explanation:
2+3+1=6, 3 divided by 6 equals to 1/2. 1/2 times 9 equals 4.5 pounds of walnuts
Let W and L be width and length of the rectangular pen respectively.
Therefore,
Circumference, C = 2W+2L= 130 yd
Area, A = LW = 1050 yd^2=> L = 1050/W
Using the circumference expression and substituting for L;
130 = 2W + 2(1050/W) = 2W+2100/W
130*W = 2W*W + 2100
130W = 2W^2 +2100
2W^2-130W+2100 = 0
Solving for W;
W= [-(-130)+/- Sqrt ((-130)^2-4(2)(2100)]/2*2 = 32.5+/- 2.5
W = 30 or 35 yd
When W = 30, L = 1050/30 = 35
When W = 35, L = 1050/35 = 30
Therefore, W = 30 yd and L = 35 yd.
Dear Foxqueen, the dependent variable is D because the grades depend on the time spent playing video games. A is not logical because the video games owned might not be played, B is illogical because the points are the product of the video games, and C is not logical because that is actually the independent variable. (rate this brainiest)
