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Ierofanga [76]
3 years ago
8

Can someone please help me with this trigonometry problem. I would highly appreciate it if you did​

Mathematics
1 answer:
dexar [7]3 years ago
5 0

Answer:

x ≈ 16.52

Step-by-step explanation:

Use the tangent ratio in the right triangle to find x

tan36° = \frac{opposite}{adjacent} = \frac{12}{x}

Multiply both sides by x

x × tan36° = 12 ( divide both sides by tan36° )

x = 12 / tan36° ≈ 16.52 ( to 2 dec. places )

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3 years ago
What is the percentage of 12(1.33)?
Alexus [3.1K]
9.022556390 is 12/ 1.33
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The table shows conversions of common units of length.
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Read 2 more answers
A ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h-48t -16t^2.
Marat540 [252]

Answer:

36 feet.

Step-by-step explanation:

We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h(t)=-48t -16t^2. We are asked to find the maximum height of the ball.

We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.

To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.

Let us find x-coordinate of parabola using formula x=-\frac{b}{2a}.

x=-\frac{-48}{2(-16)}

x=-\frac{48}{32}

x=-\frac{3}{2}

So, the x-coordinate of the parabola is -\frac{3}{2}. Now, we will substitute x=-\frac{3}{2} in our given equation to find y-coordinate of parabola.

h(t)=-48t -16t^2

h(-\frac{3}{2})=-48(-\frac{3}{2})-16(-\frac{3}{2})^2

h(-\frac{3}{2})=-24(-3)-16(\frac{9}{4})

h(-\frac{3}{2})=72-4*9

h(-\frac{3}{2})=72-36

h(-\frac{3}{2})=36

Therefore, the maximum height of the ball is 36 feet.

3 0
3 years ago
1: 1/2 km equals to how many metres?
VMariaS [17]
1.
km=kilometers
kilo=1000
1 km=1000meters
so
1/2km= 1/2 times 1000=1000/2=500meters


2. 1/4 km=1000/4=250 meters

3. 1/5 km=1000/5=200 meters

4. 2/5 km=2000/5=400 meters

5. 3/4 km=3000/4=750 meters

6. 1/8 km=1000/8=125 meters
7 0
3 years ago
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