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OLga [1]
3 years ago
15

X ^ 4 minus 16 ? factor between two squares

Mathematics
1 answer:
marysya [2.9K]3 years ago
6 0

Answer:

(x^{2} -4)(x^{2} +4)

Step-by-step explanation:

x^{4}-16

= (x^{2} -4)(x^{2} +4)

find what the square root is for the two terms

put them in brackets with different signs

General rule:

x^{2} -y^{2} = (x-y)(x+y)

Hope that helped

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To find the area of this composite shape you will have to split them into 2 shapes; a rectangle and a triangle.

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Hope this helps :)

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Aleksandr-060686 [28]

The equation of the function f(x) is f(x) = 2 sin(π/2(x + 6)) - 3

<h3>How to create the sine function?</h3>

A sine function is represented as:

f(x) = A sin(B(x + C)) + D

Where

A = Amplitude

Period = 2π/B

C = Phase shift

D = Vertical shift

The requirements in the question are:

  • Amplitude not equal to 1
  • Period not equal to 2π
  • Non-zero phase and vertical shifts

So, we can use the following assumptions

A = 2

Period = 4

C = 6

D = -3

So, we have:

f(x) = 2 sin(B(x + 6)) - 3

The value of B is

4 = 2π/B

This gives

B = π/2

So, we have:

f(x) = 2 sin(π/2(x + 6)) - 3

<h3>The amplitude, vertical shift, period of f(x)and the phase shift</h3>

Using the representations in (a), we have:

  • Amplitude = 2
  • Vertical shift = -3
  • Period = 4
  • Phase shift = 6

<h3>The graph of the function</h3>

See attachment for the graph of f(x)

<h3>The value of cos θ </h3>

Let θ = 3π

So, we have:

cos(3π)

This is calculated as:

cos(3π) = cos(2π + π)

Expand

cos(3π) = cos(2π) *cos(π) - sin(2π) *sin(π)

Evaluate

cos(3π) = -1

<h3>The value of sin θ </h3>

Let θ = 3π

So, we have:

sin(3π)

This is calculated as:

sin(3π) = sin(2π + π)

Expand

sin(3π) = sin(2π) *cos(π) + cos(2π) *sin(π)

Evaluate

sin(3π) = 0

<h3>The value of tan 2θ </h3>

Let θ = 3π

So, we have:

tan(2 * 3π)

tan(6π)

This is calculated as:

tan(6π) = tan(3π + 3π)

Evaluate

tan(3π) = 0

Read more about sinusoidal functions at:

brainly.com/question/10700288

#SPJ1

6 0
1 year ago
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