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marysya [2.9K]
2 years ago
14

Your throw your ball into a air from height of 4.2

Mathematics
1 answer:
melamori03 [73]2 years ago
3 0
4.2m
10N/kg
Hjdsdgjbcsryhbvzshkk
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Factor this x^3 + 27
masya89 [10]
(x+3)(x^2-3x+9)

this gets the x^3 while the 3x cancels out and 3*9=27

hope this helps although i didn't explain very well :)
8 0
2 years ago
Right triangle with angles 12,8 and y Pythagorean theorem
igomit [66]

Answer:

Step-by-step explanation:

4 0
3 years ago
PLEASE HELP ASAP! THANK YOU LOTS! <3
den301095 [7]

Answer:

C

Step-by-step explanation:

12 divided by 3 is 4 and 30 divided by 3 is 10

6 0
3 years ago
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a. Among a shipment of 5,000 tires, 1,000 are slightly blemished. If one purchases 10 of these tires, what is the probability th
hodyreva [135]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

3 or less than 3 tires among the 10 tires should be blemished.

There are some possibilities.

1000 tires are blemished, (5000 - 1000) = 4000 tires are not blemished.

From the 5000 tires, 10 tires can be chosen in ^{5000}C_{10} ways.

Possibility 1: <u>3 tires are blemished.</u>

Total 10 tires can be chosen with 3 blemished tires in ^{1000}C_3 \times {4000}C_7 ways.

Possibility 2:  <u>2 tires are blemished.</u>

Total 10 tires can be chosen with 2 blemished tires in ^{1000}C_2 \times ^{4000}C_8  ways.

Possibility 3: <u>1 tires are blemished.</u>

Total 10 tires can be chosen with 1 blemished tires in ^{1000}C_1 \times^{4000}C_9 ways.

Possibility 4:  <u>No tires are blemished.</u>

Total 10 tires can be chosen with no blemished tires in ^{1000}C_0 \times^{4000}C_{10} ways.

Hence, the required probability is \frac{^{1000}C_1 \times^{4000}C_9 + ^{1000}C_0 \times^{4000}C_{10} + ^{1000}C_2 \times^{4000}C_8 + ^{1000}C_3 \times^{4000}C_7}{^{5000}C_{10} }.

6 0
2 years ago
Factorise n² - 11n+ 18
11111nata11111 [884]

Step-by-step explanation:

=n2-11n+18

=n2-(9+2)n+18

=n2-9n-2n+18

=n(n-9)-2(n-9)

=(n-2)(n-9)

6 0
2 years ago
Read 2 more answers
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