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Yuri [45]
3 years ago
13

The interest on a $6,000, 6%, 60-day note receivable is

Mathematics
1 answer:
Musya8 [376]3 years ago
4 0

Answer:

The answer is c or $180

Step-by-step explanation:

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2 years ago
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Please see the photo.
Andreas93 [3]

Answer:

CE and GD

Step-by-step explanation:

A secant of a circle is a line which passes through only 2 points of the circle. So it bisects the circle at exactly 2 points. BF is not a secant because even though the points are labelled there is no line passing through. The reason why GD is a secant is because there are the points G and F and a straight line runs through them so that's why it's a secant

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3 years ago
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PLEASE HELP ME ASAP SOMEONE
Eduardwww [97]

Answer:

E (3,-1)   D (-2, -2)   G (-1, 3)    F (3, 2)

Step-by-step explanation:

90 degrees = (y, -x)

that means you take the ordered pair you want to rotate and plug the x and y into the new spots.  

for example, point E is at (1,3) so the point rotated 90 degrees is (3,-1)

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2 years ago
Simplify: 2⁶X5⁴X3¹²/2²x5²x3⁴​
Sholpan [36]

Step-by-step explanation:

2⁶X5⁴X3¹²/2²x5²x3⁴

2⁴ × 5²×3⁸

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2 years ago
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Describe the rotation of J
Serga [27]

Answer:

The coordinates of J' when rotating by 90° counterclockwise will be: J'(3, 1)

The coordinates of J' when rotating by 90° clockwise will be: J'(-3, -1)

Step-by-step explanation:

Square JKLM with vertices

  • J(1, -3)
  • K(5, 0)
  • L(8, -4)
  • M(4, -7)

We have to determine the answer for the image J' of the point (1, -3) when we rotate the point by 90° counterclockwise, we need to switch x and y, make y negative.

In other words, the rule to rotate a point by 90° counterclockwise.

P(x, y) → P'(-y, x)

As we are given that J(1, -3), so the coordinates of J' will be:

J(1, -3) → J'(3, 1)

Therefore, the coordinates of J' when rotating by 90° counterclockwise will be:  J'(3, 1).

When the point is rotated by 90° clockwise, we need to switch x and y, make x negative.

In other words, the rule to rotate a point by 90° clockwise.

P(x, y) → P'(y, -x)

As we are given that J(1, -3), so the coordinates of J' will be:

J(1, -3) → J'(-3, -1)

Therefore, the coordinates of J' when rotating by 90° clockwise will be:  J'(-3, -1)

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2 years ago
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