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Yuri [45]
3 years ago
13

The interest on a $6,000, 6%, 60-day note receivable is

Mathematics
1 answer:
Musya8 [376]3 years ago
4 0

Answer:

The answer is c or $180

Step-by-step explanation:

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FIND THE EXACT AREA PLEASE HELPPPP ILL GIVE BRAINLIESTTTT
Ede4ka [16]

Answer:

555.94

Step-by-step explanation:

16 x 11 = 176/2

88

since there are two of the same triangle

88 x 2

176

11 is the radius

A = \pix^{2}

A = 3.14 ( pie is 3.14, if not then pi) x (11x11)

A = 3.14 x 121 (or 121\pi)

A = 379.94

379.94 + 176 (or 121pi + 176)

555.94

4 0
2 years ago
Y = 2x - 2 , y = 2x + 9 . what's the solution ?
beks73 [17]
If you solve it, you get 2=9, which is incorrect. That means there's no solution.
3 0
3 years ago
Read 2 more answers
Keller lives in a city with 54,706 people. Dawson lives in a city with 45,802 people. How can the two cities that Keller and Daw
Genrish500 [490]

Answer:

54,706 > 45,802

Step-by-step explanation:

Well, as you know, the > symbol means that one number has a greater value than another. For example, 2 > 1. The way we can find that out is using subtraction. Take 54,706 - 45,802, and if that number is positive, then the first number is greater than the other.

54,706 - 45,802 = 8,904

8,904 is a positive.

Therefore, 54,706 > 45,802.

6 0
3 years ago
Read 2 more answers
Cos^2 x+4sin^2 x/2=1
lana [24]

Let\ \dfrac{x}{2}=a,\ therefore\ x=2a.\\\\\cos^2x+4\sin^2\dfrac{x}{2}=\cos^22a+4\sin^2a\\\\\text{use}\ \cos2x=\sin^2x-\cos^2x\\\\=(\sin^2a-\cos^2a)^2+4\sin^2a\\\\\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\=(\sin^2a)^2-2(\sin^2a)(\cos^2a)+(\cos^2a)^2+4\sin^2a\\\\=\sin^4a-2\sin^2a\cos^2a+\cos^4a+4\sin^2a\\\\=\underbrace{\sin^4a+2\sin^2a\cos^2a+\cos^4a}_{(*)}-4\sin^2a\cos^2a+4\sin^2a\\\\\text{use}\ (*)\qquad(a+b)^2=a^2+2ab+b^2

=\underbrace{(\sin^2a)^2+2\sin^2a\cos^2a+(\cos^2a)^2}_{(*)}-4\sin^2a(\cos^2a-1)\\\\=(\sin^2a+\cos^2a)^2-4\sin^2a(\cos^2a-1)\\\\\text{use}\ \sin^2a+\cos^2a=1\to\sin^2a=\cos^2a-1\\\\=1^2-4\sin^2a(\sin^2a)=1-4\sin^4a=1-(2\sin^2a)^2

\cos^22a+4\sin^2a=1\\\\1-(2\sin^2a)^2=1\qquad\text{subtract 1 from both sides}\\\\-(2\sin^2a)^2=0\to2\sin^2a=0\qquad\text{divide both sides by 2}\\\\\sin^2a=0\to\sin a=0\\\\a=k\pi\ for\ k\in\mathbb{Z}\\\\\dfrac{x}{2}=k\pi\qquad\text{multiply both sides by 2}\\\\\boxed{x=2k\pi\ for\ k\in\mathbb{Z}}

6 0
3 years ago
Please show your work! thank you
Bingel [31]
You want to write them both into slope intercept form (y=mx+b) so the first one is y=2x-9/2. For the second one you can start converting them until you get y=3x+kx+2 so you need to find the value of K that adds to to equal to 2 because parallel lines have the same slope so k would = -1
6 0
3 years ago
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