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Alex
3 years ago
12

A shoe manufacturer was investigating the weights of men's soccer cleats. He felt that the weight of these cleats was less than

the average weight of 10 ounces. After a random sample of 13 pairs of cleats, he found that sample mean was 9.63 and the standard deviation was .585. At a significance level of .05, can it be concluded that the researcher was correct?
Show work
Mathematics
1 answer:
aleksklad [387]3 years ago
6 0

Answer:

 The conclusion is that the researcher was correct

Step-by-step explanation:

From the question we are told that

     The sample size is  n =  13

    The sample mean is  \= x =  9.63

     The standard deviation is  s =  0.585

      The significance level is  \alpha  =  0.05

The Null Hypothesis is  H_o :  \mu = 0

The Alternative  Hypothesis  is  H_a =  \mu < 10

The test statistic is  mathematically represented as

          t =  \frac{\= x - \mu }{\frac{s}{\sqrt{n} } }

Substituting values

          t =  \frac{9.63  - 10 }{\frac{0.585}{\sqrt{13} } }

         t =  -  2.280

Now the critical value for \alpha is  

     t_{\alpha } = 1.645

This obtained from the critical value table

  So comparing the critical value of alpha and the test value we see that the test value is less than the critical value so the Null Hypothesis is rejected

 The conclusion is that the researcher was correct

 

 

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kvv77 [185]

Given the triangle

PQR

with points

P(8,0)

Q(6,2)

R(-2,-4)

And the triangle

P'Q'R'

with points

P'(4,0)

Q'(3,1)

R'(-1,-2)

Part A. Scale factor

Using the vertex

P( 8, 0)

P'(4,0)

the dilatation factor is given by

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The triangle has a dilatation factor of 1/2

Part B:

P''Q''R'' after using P'Q'R' reflected about the y axis

to make a reflection over the y axis

coordinates (x,y) turn into coordinates (-x,y)

as follows

P^{\prime}(4,0)\rightarrow P^{\prime\prime}(-4,0)Q^{\prime}(3,1)\rightarrow Q^{\prime\prime}(-3,1)R^{\prime}(-1,-2)\rightarrow R^{\prime\prime}(1,-2)

Then triangle P''Q''R'' has coordinates

P''(-4,0)

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8 months ago
3<br> x<br> +<br> y<br> =<br> −<br> 14<br> 4<br> x<br> +<br> 4<br> y<br> =<br> −<br> 16
aev [14]

Answer:

y=1

x=-5

Step-by-step explanation:

3x+y=-14

4x+4y=-16

y=-3x-14

4x+4y=-16

y=-3x-14

4(-3x-14)+4x=-16

y=-3x-14

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fiasKO [112]

Answer:

A. Solutions are: x = 2, y = 1.

B. Solutions are: x = 3, y = 2.

C.

1. Inconsistent

2. Inconsistent

3. Consistent

Step-by-step explanation:

A. Solutions of each system of linear equations by substitution method:

Equation 1:      3x - 2y = 4

Equation 2:               x = 2y

<u>Step 1:</u> Substitute x = 2y into the Equation 1:

3(2y) - 2y = 4

6y - 2y = 4

4y = 4

Step 2: Divide both sides of the equation by 4 to isolate y:

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x = 2  

Therefore, the solutions are:  x = 2, y = 1.

B. Find the solutions of each system of linear equations by elimination method:  

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Equation 2:        x + y = 5

<u>Step 1:</u> Multiply Equation 2 by 2:  

2(x + y) =  5(2)

2x + 2y = 10

<u>Step 2:</u> Subtract Equation 1 from the equation derived from Step 1,  2x + 2y = 10:

   2x + 2y = 10

-  <u>2x +  y  =   8</u>

        y =   2

Step 3: Plug in y =  2 into Equation 1, 2x + y = 8 to solve for x:

2x + y = 8

2x + (2) = 8

<u>Step 4:</u> subtract both sides of the equation by 2 to isolate x:

2x + 2 - 2 = 8 - 2

2x = 6

<u>Step 5:</u> Divide both sides of the equation by 2 to solve for x:

\frac{2x}{2}  = \frac{6}{2}

x = 3.

The solutions are: x = 3, y = 2.

C:

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2. Inconsistent  

3. Consistent (infinitely many solutions)

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