Answer:
<h3>Standard unit is a standard measure that remains the same whenever, wherever and by whoever it is used. eg: The standard unit of time is second.</h3>
Answer:
Given:
Resistance (R) = 100 Ω
Current (I) = 5 A
Time (t) = 2 hours
To Find:
Heat developed (H) in the electric iron
Explanation:
Formula:
Substituting values of I, R & t in the equation:
Heat developed (H) in the electric iron = 15 kWh
Answer:
when the center of gravity is within the washing area, the torque returns in the body to its initial position and is in a stable equilibrium
Explanation:
The concept of center of gravity is equivalent to the concept of center of mass, in this place all external forces applied can be considered.
When we analyze the balance of a body that is the torque it is the one that defines the balance
τ = F xd
If the torque tends to restore the body to the initial position the balance is stable, but if the torque has to increase the body's rotation the balance is unstable
. When the body tends to rotate the torque with respect to the pivot point at the base it decreases because the distance from the center of gravity to the end of the base decreases in value, but it has to return it to the initial position, the balance is stable. The critical point of this process is when the center of gravity is at the limit of the body base area in this case the torque is zero; If the body rotates a little more the center of gravity is outside the base, the torque changes sign and has to increase the turn, going to an unstable balance.
In summary, when the center of gravity is within the washing area, the torque returns in the body to its initial position and is in a stable equilibrium.
Answer:
L = 0.48 H
Explanation:
let L be the inductance, Irms be the rms current, Vrms be the rms voltage and Vmax be the maximum voltage and XL be the be the reactance of the inductor.
Vrms = Vmax/(√2)
= (3.00)/(√2)
= 2.121 V
then:
XL = Vrms/I
= (2.121)/(2.50×10^-3)
= 848.528 V/A
that is L = XL/(2×π×f)
= (848.528)/(2×π×(280))
= 0.482 H
Therefore, the inductance needed to kepp the rms current less than 2.50mA is 0.482 H.
