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Olenka [21]
3 years ago
13

The laboratory is based on the assumption that at the two points of the motion being considered, the mass is at rest. What kind

of energy does not need to be included under these experimental conditions
Physics
1 answer:
Yuri [45]3 years ago
7 0

Answer:

In summary kinetic energy is not necessary

Explanation:

In this problem we are asked to indicate what type of energy does not need to be considered.

As they indicate that the masses do not move, scientific energy is defined by

      K = ½ m v²

Since the velocities of the mass are zero, this energy is zero, so it is not necessary to take them into account in our analyzes.

In summary kinetic energy is not necessary

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18. How much force would it take to push another, larger friend who has a mass of 70 Kg to accelerate
oksano4ka [1.4K]

Answer:

280N

Explanation:

f = mass x acceleration

4 0
2 years ago
3. What is the main difference between a physical change and a chemical
Lana71 [14]

Answer:

B and D could both be right as they are quit similar.

Consider two rods of the same length and diameter,

Increasing the diameter of one would change the expansion qualities of that rod even though there would be no chemical changes,

However, leaving the physical appearance of both rods the same while applying a reactive substance (acid or something) to one of the rods would not necessarily change the physical appearance of that rod but could make a considerable change in the  physical properties of that rod.

3 0
3 years ago
Steam at 100°C is condensed into a 38.0 g aluminum calorimeter cup containing 280 g of water at 25.0°C. Determine the amount of
KonstantinChe [14]

Answer:

7.2g

Explanation:

From the expression of latent heat of steam, we have

Heat supplied by steam = Heat gain water + Heat gain by calorimeter

mathematically,

m_{s}c_{w} \alpha _{w} + m_{s}l=m_{w}c_{w} \alpha _{w} +m_{c}c_{c} \alpha c_{c}

L=specific latent heat of water(steam)=2268J/g

c_{w}=specific heat capacity=4.2J/gK

c_{c}=specific heat capacity of calorimeter =0.9J/gk

m_{w}=280g

m_{c}=38g

α=change in temperature

\alpha _{c}=(40-25)=15

\alpha _{w}=(40-25)=15

\alpha _{s}=(100-40)=60

Note: the temperature of the calorimeter is the temperature of it content.

From the equation, we can make m_{s} the subject of formula

m_{s}=\frac{m_{w}c_{w} \alpha +m_{c}c_{c}\alpha}{c_{w}\alpha +l}

Hence

m_{s}=\frac{(280*4.2*15) +(38*0.9*15)}{(4.2*60) +2268} \\m_{s}=\frac{18153}{2520}\\ m_{s}=7.2g

Hence the amount of steam needed is 7.2g

6 0
3 years ago
To ya is modeling the discovery of electromagnetic induction. Which procedures should she use
Vedmedyk [2.9K]

Answer:

moving a magnet into a coil of wire in a closed circuit.

Ed 2020

8 0
3 years ago
What is the initial position
labwork [276]

Answer:

Initial position of a body is the position of the body before accelerating or increasing its velocity the position changes and then that position is the final position.

hope it is helpful...

6 0
3 years ago
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