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JulsSmile [24]
3 years ago
9

You have 185 mL of an acid with an unknown concentration. To determine the concentration you decide to use a 0.85 M solution of

sodium hydroxide to titrate the acid. After the titration you determined that it took 35.7 mL of the 0.85 M solution of sodium hydroxid to reach the endpoint. What is the acids concentration?
Chemistry
1 answer:
kondor19780726 [428]3 years ago
8 0

Explanation:

The given data is as follows.

       M_{1} = ?,         M_{2} = 0.85 M

       V_{1} = 185 mL,     V_{2} = 35.7 mL

where, M_{1} is concentration of acid

            V_{1} is the volume of acid

            M_{2} is the concentration of base

            V_{2} is the volume of base

According to the neutralization formula.

          M_{1} \times V_{1} = M_{2} \times V_{2}

Now, substituting the given values into the above formula as follows.

          M_{1} \times V_{1} = M_{2} \times V_{2}

          M_{1} \times 185 mL = 0.85 M \times 35.7 mL

                       M_{1} = 0.164 M

Thus, we can conclude that concentration of acid is 0.164 M.

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Answer:

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Firstly, we convert what we have to percentage compositions.

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Therefore, the answers for the blanks are low concentrated and high concentrated.




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