Question

You have 185 mL of an acid with an unknown concentration. To determine the concentration you decide to use a 0.85 M solution of sodium hydroxide to titrate the acid. After the titration you determined that it took 35.7 mL of the 0.85 M solution of sodium hydroxid to reach the endpoint. What is the acids concentration?

Answer 1

Explanation:

The given data is as follows.

       $M_{1}$ = ?,         $M_{2}$ = 0.85 M

       $V_{1}$ = 185 mL,     $V_{2}$ = 35.7 mL

where, $M_{1}$ is concentration of acid

            $V_{1}$ is the volume of acid

            $M_{2}$ is the concentration of base

            $V_{2}$ is the volume of base

According to the neutralization formula.

          $M_{1} \times V_{1}$ = $M_{2} \times V_{2}$

Now, substituting the given values into the above formula as follows.

          $M_{1} \times V_{1}$ = $M_{2} \times V_{2}$

          $M_{1} \times 185 mL$ = $0.85 M \times 35.7 mL$

                       $M_{1}$ = 0.164 M

Thus, we can conclude that concentration of acid is 0.164 M.