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Sedbober [7]
3 years ago
8

Directions: Name each of the following compounds. If a name is given, write the formula.

Chemistry
1 answer:
dsp733 years ago
5 0

Answer:

1. Sodium Oxide

2. Barium Sulfide

3. Copper (II) sulfate

4. Mercury (II) chloride

5. Silver Nitrate

6. CuO

7. FeCl3

8. Zn (NO3)2

9. Mg (OH)2

10. SnS

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Consider the following reaction: CO(g)+2H2(g)⇌CH3OH(g) This reaction is carried out at a different temperature with initial conc
Anni [7]

Answer:

Ka = 4.76108

Explanation:

  • CO(g) + 2H2(g) ↔ CH3OH(g)

∴ Keq = [CH3OH(g)] / [H2(g)]²[CO(g)]

                      [ ]initial         change         [ ]eq

CO(g)              0.27 M       0.27 - x        0.27 - x

H2(g)              0.49 M       0.49 - x        0.49 - x

CH3OH(g)          0                0 + x               x = 0.11 M

replacing in Ka:

⇒ Ka = ( x ) / (0.49 - x)²(0.27 - x)

⇒ Ka = (0.11) / (0.49 - 0.11)² (0.27 - 0.11)

⇒ Ka = (0.11) / (0.38)²(0.16)

⇒ Ka = 4.76108

7 0
3 years ago
If you were to conduct an experiment to answer the question, "Does the volume of a caffeinated drink affect your reaction time?”
Ann [662]

Answer:

A Type of Drink

Explanation:

A controlled variable remains constant throughout the experiment.

In such experiment, you'd test the volume of one single caffeinated drink. You'd have to use the same type of drink every trial.

4 0
2 years ago
Which chemical formula corresponds to this structural formula?
lys-0071 [83]
I think the answer is choice D
8 0
3 years ago
Read 2 more answers
A chemist mixes 75.0 g of an unknown substance at 96.5°C with 1,150 g of water at 25.0°C. If the final temperature of the system
AleksAgata [21]
To do this problem it is necessary to take into account that the heat given by the unknown substance is equal to the heat absorbed by the water, but considering the correct sign:

-m\cdot c_e\cdot \Delta T = m_w\cdot c_e_w\cdot \Delta T_w

Clearing the specific heat of the unknown substance:

c_e = \frac{m_w\cdot c_e_w\cdot \Delta T_w}{m\cdot \Delta T} = -\frac{1\ 150\ g\cdot 4.184\frac{J}{g\cdot ^\circ C}\cdot (37.1 - 25.0)^\circ C}{75\ g\cdot (37.1 - 96.5)^\circ C}

c_e = -\frac{1\ 150\ g\cdot 4.184\frac{J}{g\cdot ^\circ C}\cdot 12.1^\circ C}{75\ g\cdot (-59.4)^\circ C} = \bf 13.07\frac{J}{g\cdot ^\circ C}
6 0
3 years ago
What scientific instrument is capable of measuring very small masses?​
marusya05 [52]

Answer:

Electronic balances.

Explanation:

5 0
3 years ago
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