Answer:
0.093 mole of C₆H₁₂.
Explanation:
We'll begin by calculating the molar mass of C₆H₁₂. This can be obtained as follow:
Molar mass of C₆H₁₂ = (12×6) + (12×1)
= 72 + 12
= 84 g/mol
Finally, we shall determine the number of mole in 7.8 g of C₆H₁₂. This can be obtained as follow:
Molar mass of C₆H₁₂ = 84 g/mol
Mass of C₆H₁₂ = 7.8 g
Mole of C₆H₁₂ =?
Mole = mass / molar mass
Mole of C₆H₁₂ = 7.8 / 84
Mole of C₆H₁₂ = 0.093 mole
Thus, 7.8 g contains 0.093 mole of C₆H₁₂.
Answer:
In aqueous solution the pH scale varies from 0 to 14, which indicates this concentration of hydrogen. Solutions with pH less than 7 are acidic (the value of the exponent of the concentration is higher, because there are more ions in the solution) and alkaline (basic) those with a pH higher than 7. If the solvent is pure water, the pH = 7 indicates neutrality of the solution
Explanation:
PH is a measure of how acidic or basic a liquid is. Specifically, from a dissolution. The acidity of a solution is essentially due to the concentration of hydrogen ions dissolved in it. In reality, the ions are not found alone, but are in the form of hydronium ions consisting of one oxygen molecule and three positively charged hydrogen. PH precisely measures this concentration. And to do it, we can use simple and very visual methods.
So diffusion is inversely proportional to mass !
so as mass of the particle increases, diffusion decreases !
Answer:
d = 0.9 g/L
Explanation:
Given data:
Number of moles = 1 mol
Volume = 24.2 L
Temperature = 298 K
Pressure = 101.3 Kpa (101.3/101 = 1 atm)
Density of sample = ?
Solution:
PV = nRT (1)
n = number of moles
number of moles = mass/molar mass
n = m/M
Now we will put the n= m/M in equation 1.
PV = m/M RT (2)
d = m/v
PM = m/v RT ( by rearranging the equation 2)
PM = dRT
d = PM/RT
The molar mass of neon is = 20.1798 g/mol
d = 1 atm × 20.1798 g/mol / 0.0821 atm. L/mol.K × 273K
d = 20.1798 g/22.413 L
d = 0.9 g/L
