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IrinaK [193]
3 years ago
14

What is the slope of this line (2,3)?3 -3/4 43/4 pllzzzz hurry!!!

Mathematics
1 answer:
ivann1987 [24]3 years ago
5 0

3/4. The line is aming to 3 sorry im not that smart


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A line passes through the points (8, 1) and (6, 7). What is the slope of the line? Answer choices: A)-3 B) -1/3 C) 1/3 D)3
Fittoniya [83]

Answer:

a) -3

Step-by-step explanation:

3 0
3 years ago
It is currently 0 degrees outside and the temperature is dropping 4 degrees every hour. The temperature after h hours is -4h. Ex
Ymorist [56]

Answer:

-4x3.5=-14

Step-by-step explanation:

divide -14 by -4 wich = 3.5

6 0
2 years ago
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Solve for r in the scientific formula d = rt.<br><br> r = _______
marta [7]
R = d/t is the answer. Hope this helped
4 0
3 years ago
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Patrick has just finished building a pen for his new dog. The pen is 3 feet wider than it is long. He also built a doghouse to p
zalisa [80]

General Idea:

(i) Assign variable for the unknown that we need to find

(ii) Sketch a diagram to help us visualize the problem

(iii) Write the mathematical equation representing the description given.

(iv) Solve the equation by substitution method. Solving means finding the values of the variables which will make both the equation TRUE

Applying the concept:

Given: x represents the length of the pen and y represents the area of the doghouse

<u>Statement 1: </u>"The pen is 3 feet wider than it is long"

Length \; of\; the \; pen = x\\ Width \; of\; the\; pen=x+3

------

<u>Statement 2: "He also built a doghouse to put in the pen which has a perimeter that is equal to the area of its base"</u>

Area \; of\; the\; Dog \; house=y\\ Perimeter \; of\; Dog\; house=y

------

<u>Statement 3: "After putting the doghouse in the pen, he calculates that the dog will have 178 square feet of space to run around inside the pen."</u>

Area \; of \; the\; Pen - Area \;of \;the\;Dog \;House=\;Space\;inside\;Pen\\ \\ x \cdot (x+3)-y=178\\ Distributing \;x\;in\;the\;left\;side\;of\;the\;equation\\ \\ x^2+3x-y=178\Rightarrow\; 1^{st}\; Equation\\

------

<u>Statement 4: "The perimeter of the pen is 3 times greater than the perimeter of the doghouse."</u>

Perimeter\; of\; the\; Pen=3\; \cdot \; Perimeter\; of\; the\; Dog\; House\\ \\ 2(x \; + \; x+3)=3 \cdot y\\ Combine\; like\; terms\; inside\; the\; parenthesis\\ \\ 2(2x+3)=3y\\ Distribute\; 2\; in\; the\; left\; side\; of\; the\; equation\\ \\ 4x+6=3y\\ Subtract \; 6\; and \; 3y\; on\; both\; sides\; of\; the\; equation\\ \\ 4x+6-3y-6=3y-3y-6\\ Combine\; like\; terms\\ \\ 4x-3y=-6 \Rightarrow \; \; 2^{nd}\; Equation\\

Conclusion:

The systems of equations that can be used to determine the length and width of the pen and the area of the doghouse is given in Option B.

178=x^2+3x-y\\ \\ -6=4x-3y

8 0
3 years ago
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The outside diameter of the igloo is 12 feet. The thickness of each block of ice that was used to construct the igloo is 1.5 fee
mojhsa [17]
The first thing we are going to do for this case is to model the igloo as a hemisphere.
 The volume of the hemisphere is:
 V = ((4/3) * (pi) * (r ^ 3)) / 2
 Where,
 r: sphere radio
 We have then that the internal diameter is:
 di = 12-1.5
 di = 10.5 feet
 So the radio is:
 r = di / 2
 r = 10.5 / 2
 r = 5.25 feet
 Substituting values:
 V = ((4/3) * (pi) * ((5.25) ^ 3)) / 2
 V = 303.1 feet ^ 3
 Answer:
 
the amount of space of the living area inside the igloo is:
 
V = 303.1 feet ^ 3
6 0
3 years ago
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