The population of the town in 1960 is 48.80 thousands
<h3>How to determine the population in 1950?</h3>
The equation of the model is given as:
f(t) = 42e^(0.015t)
1960 is 10 years after 1950.
This means that:
t = 10
Substitute t = 10 in f(t) = 42e^(0.015t)
f(10) = 42e^(0.015 * 10)
Evaluate
f(10) = 48.80
Hence, the population of the town in 1960 is 48.80 thousands
Read more about exponential functions at:
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Answer:
Step-by-step explanation:
if A=1/2 bh
to solve for b
2A=bh
b=2A/h
Answer:
Um you didnt attach a file or anything make one again and ill answer it just attach a screenshot of the problem
Step-by-step explanation:
Answer:
-5
Step-by-step explanation:
The equation is in slope intercept form. 
8 replaces b, so it is the y-intercept.
-5 replaces m, so it is the slope.
Answer:
x+3y = 6
or, x = 6-3y.................(1)
3x+5y =6..........(2)
Substituting x = 6-3y in equation (2),
3 (6 - 3 y)+5 y =6
or, 18 - 9y +5y=6
or, y = 3
x = 6 - 3y = 6- 3.-3 = -3
