<span>29+10j= -11
</span><span>29+10j - 29 = -11 - 29 (subtract 29 to both sides)
10j = -40
10j/10 = -40/10 (divide both sides by 10)
j = -4
</span>
Given:
The given digits are 1,2,3,4,5, and 6.
To find:
The number of 5-digit even numbers that can be formed by using the given digits (if repetition is allowed).
Solution:
To form an even number, we need multiples of 2 at ones place.
In the given digits 2,4,6 are even number. So, the possible ways for the ones place is 3.
We have six given digits and repetition is allowed. So, the number of possible ways for each of the remaining four places is 6.
Total number of ways to form a 5 digit even number is:


Therefore, total 3888 five-digit even numbers can be formed by using the given digits if repetition is allowed.
Answer:
Yes
Step-by-step explanation:
Hope this helps!
Good Luck!
Answer:

Step-by-step explanation:
We are given that fraction

We have to find the expression which is equivalent to given fraction .


Substitute the values then, we get

We know that

Using the property then, we get


This is required expression which is equivalent to given expression.
Answer:
b
Step-by-step explanation:
Given K is the midpoint of JL, then
JK = KL ← substitute values
6x = 3x + 3 ( subtract 3x from both sides )
3x = 3 ( divide both sides by 3 )
x = 1
Hence
JK = 6x = 6 × 1 = 6
KL = 3x + 3 = (3 × 1) + 3 = 3 + 3 = 6
JL = 6 + 6 = 12