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2 years ago

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tiny pulls with a force of 240n and utoy pull with a force of 200n. The angle between the force is 37 degree. What is th magnitu

de of the resultant force on the basket?

1 answer:

Arlecino [84]2 years ago

8 0

Answer:

R=417.46 N

Step-by-step explanation:

If ans is correct you can ask me for explanation .

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A local cinema found that if the price of admission was $17$⁢17, the attendance was about 20502050 customers per week. When the

Liula [17]

Answer:

A = -10*p + 2220

Step-by-step explanation:

To write a linear equation let define

A = attendance

m = slope of the line

b = intercept of the line

p = Price of admision

let´s find m, using the two points (p,A)

point 1 = (17, 2050)

point 2 = (12, 2100)

m = (2100 – 2050)/(12-17) = -10

Replacing m in the equation

A=-10p+b

To find b, let´s use point 1

2050 = -10*17 + b

B = 2050 + 170

b = 2220

finally, the equation is

A = -10*p + 2220

8 0

3 years ago

Given the points (8,9) and (2,7) find the slope M=

Goshia [24]

Answer:

1/3

Step-by-step explanation:

7-9=-2

2-8=-6

2/6 is 1/3 when simplified

3 0

3 years ago

The exponential modeled below represents the number of bacteria growing after a certain number or hours has passed.

lorasvet [3.4K]

Answer:

I would say D because if you count how much they go up it's close. but if you dont agree I could also assume B.

8 0

3 years ago

Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the

ziro4ka [17]

Answer:

a) $\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}$

The sample deviation for this case is s=30.23

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=9-1=8$

The Confidence interval is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and the critical values are:

$\chi^2_{\alpha/2}=20.09$

$\chi^2_{1- \alpha/2}=1.65$

And replacing into the formula for the interval we got:

$\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

Part b

For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

4 0

3 years ago

Each side of a square rug is 3ft 2in long. Peg has 20ft of braid to use as trim on the four sides of the rug. How much braid wil

stepan [7]

Answer:

7ft 8in is left over

Step-by-step explanation:

5 0

3 years ago