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Lunna [17]
3 years ago
10

1. which two types of clouds indicate fair weather?

Mathematics
2 answers:
Svetllana [295]3 years ago
8 0

Answer:

a) cirrus and cumulus

Step-by-step explanation:

The two types of clouds that indicate fair weather are :

a) cirrus and cumulus clouds.

Cirrus clouds are usually white and predict fair to pleasant weather.

Cumulus clouds are also called fair weather clouds and look like floating cotton in the sky.

shepuryov [24]3 years ago
6 0
<span>The two types of clouds that indicate fair weather are cirrus and cumulus. Cirrus is a type of clouds that is compared and nicknamed sometimes as the hairs of an angel because it is so thin. Unlike cirrus that appears at high altitudes, cumulus generally are formed closer to the earth surface.</span>
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What is the value of x?
lbvjy [14]
The vaue of x is 23 cm
5 0
3 years ago
Read 2 more answers
The total number of​ restaurant-purchased meals that the average person will eat in a​ restaurant, in a​ car, or at home in a ye
zloy xaker [14]

Answer:

Number of​ restaurant-purchased meals eaten in a​ restaurant = 70

Number of​ restaurant-purchased meals eaten in a​ car = 22

Number of​ restaurant-purchased meals eaten in a​ home = 60

Step-by-step explanation:

Let the number of people that will eat in a restaurant be R.

Let the number of people that will eat in a car be C.

Let the number of people that will eat in a home be H.

From the information given in the problem we have,

R+C+H = 152 ____equation (1)

C+H-R = 12 ____equation (2)

R = H+10 ____equation (3)

1) Plugging in R=H+10 from equation 3 into the equation 2, we get

C+H-R=12

=> C+H-(H+10)=12

=> C+H-H-10=12

2) Cancelling out +H and -H, we get

C-10=12

3) Add 10 to both sides

C-10+10=12+10

4) Cancelling out -10 and +10, we get

C=22

5) Plugin C=22 in equation 1, we have

R+C+H = 152

=> R+22+H=152

Subtract 22 from both sides,

R+22+H-22=152-22

Cancelling out +22 and -22 from the left side, we get

R+H=130 ____let it be equation (4)

6) Plugin C=22 in equation 2, we have

C+H-R = 12

22+H-R = 12

Subtracting 22 from both the sides, we get

22+H-R-22 = 12-22

Cancelling out +22 and -22 from the left side,

H-R = -10 ____let it be equation (5)

7) Adding equation 4 and equation 5, we get

(R+H)+(H-R) = 130 + (-10)

=> R+H+H-R = 130-10

8) Cancelling out R and -R from the left side, we get

2H = 120

9) Dividing both sides by 2, we get

\frac{2H}{2} = \frac{120}{2}

10) Cancelling out the 2's from the left side, we have

H=60

11) Plugging in C=22 and H=60 in the equation 1, we have

R+C+H = 152

=> R+22+60=152

=> R + 82 = 152

12) Subtracting 82 from both the sides, we get

R + 82 -82 = 152 -82

13) Cancelling out +82 and -82 from the left side, we get

R = 70

<em>So, C=22, H=60, R=70</em>

8 0
3 years ago
8,11,14,17 and you have to find the 74th term
astra-53 [7]

Answer:

227 is the 74th term of your question.

7 0
3 years ago
monica and three friends went out to dinner. the bill came down to $60. they had excellent service so they wanted to leave a 20%
netineya [11]

Answer:

$72

Step-by-step explanation:

60 * 20% = $12


Hope this helps. Have a great day. :)

-wfz

5 0
3 years ago
Please help to solve this!
Mashutka [201]
Yeah its definitely 5!
4 0
3 years ago
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