Answer:
2 KNO₃ + 10 K → 5 K₂O + N₂ (option 1)
Explanation:
1. 2 KNO₃ + 10 K → 5 K₂O + N₂
We have in reactant side:
2 K, 2N, 6O and 10 K. In conclussion, 12 K, 2N and 6 O
We have in product side.
10 K, 5O and 2 N
This equation is unbalanced
2. 2 SO₂ + O₂ → 2 SO₃
In reactant side we have 2 S and 6 O
In product side we have 2 S and 6 O
3. SF₄ + 3 H₂O → H₂SO₃ + 4 HF
In reactant side we have 1 S, 4F, 6 H and 3 O
In product side we have 1 S, 4F, 6 H and 3 O
