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kompoz [17]
3 years ago
8

What is the standard cell potential of a cell made of theoretical metals ma/ma2+ and mb/mb2+ if the reduction potentials are –0.

19 v and –0.85 v, respectively?
Chemistry
2 answers:
Yuki888 [10]3 years ago
6 0
The standard cell potential of a cell made of theoretical metals ma/ma2+ and mb/mb2+ is to be determined. We are given their reduction potentials:

-0.19 v for A
-0.85 v for B

To solve for the standard cell potential, examine the reaction and

the standard cell potential for this case is (-0.19- (-0.85)) v = -0.66 v<span />
love history [14]3 years ago
5 0

The correct answer is +0.66 V

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A gas has a volume of 62.65L at O degrees Celsius and 1 atm. At what temperature in Celsius would the volume of the gas be 78.31
Anastaziya [24]

Answer:

The volume of the gas will be 78.31 L at 1.7 °C.

Explanation:

We can find the temperature of the gas by the ideal gas law equation:

PV = nRT

Where:

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V: is the volume

T: is the temperature

R: is the gas constant = 0.082 L*atm/(K*mol)

From the initial we can find the number of moles:

n = \frac{P_{1}V_{1}}{RT_{1}} = \frac{1 atm*62.65 L}{(0.082 L*atm/K*mol)*(0 + 273)K} = 2.80 moles

Now, we can find the temperature with the final conditions:

T_{2} = \frac{P_{2}V_{2}}{nR} = \frac{612.0 mmHg*\frac{1 atm}{760 mmHg}*78.31 L}{2.80 moles*0.082 L*atm/(K*mol)} = 274.7 K

The temperature in Celsius is:

T_{2} = 274.7 - 273 = 1.7 ^{\circ} C

Therefore, the volume of the gas will be 78.31 L at 1.7 °C.

I hope it helps you!            

8 0
3 years ago
Put this in scientific notation. 10 m to centimeters and 37.5 g/mL to kg/L
noname [10]

1m = 100cm

so 10m = 100*10 = 1000cm or in scientific notation 1.00x10^3 cm

1g = 1/1000kg

1mL = 1/1000L

so 1g/mL = (1/1000)/(1/1000)kg/L

=1kg/L

37.5g/mL = 37.5kg/L or 3.75*10^1 kg/L


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The scientist that performed the cathode ray experiment leading to the discovery of electrons is J.J. Thomson.

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