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KonstantinChe [14]
4 years ago
6

Solve 14n+ 6p-8n= 18p for n.

Mathematics
2 answers:
garik1379 [7]4 years ago
5 0

Answer:

<h2>n = 2p</h2>

Step-by-step explanation:

14n+6p-8n=18p\qquad\text{combine like terms}\\\\(14n-8n)+6p=18p\qquad\text{subtract}\ 6p\ \text{from both sides}\\\\6n=12p\qquad\text{divide both sides by 6}\\\\n=2p

alexdok [17]4 years ago
4 0

Answer:

Step-by-step explanation:

14n+6p-8n=18p

6n=12p

n=2p

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Devide (a2+ 7a+ 12)÷ (a+3)​
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Answer:

(a - 3) • (a - 4)

Step-by-step explanation:

The first term is,  a2  its coefficient is  1 .

The middle term is,  -7a  its coefficient is  -7 .

The last term, "the constant", is  +12

Multiply the coefficient of the first term by the constant   1 • 12 = 12

Find two factors of  12  whose sum equals the coefficient of the middle term, which is   -7 .

     -12    +    -1    =    -13

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     -4    +    -3    =    -7    That's it

Rewrite the polynomial splitting the middle term using the two factors, -4  and  -3

                    a2 - 4a - 3a - 12

Add up the first 2 terms, pulling out like factors :

                   a • (a-4)

             Add up the last 2 terms, pulling out common factors :

                   3 • (a-4)

Add up the four terms

                   (a-3)  •  (a-4)

Really hope this helps :)

           

5 0
3 years ago
For each of the values of h given, when x is increased from 1 to 1+h, work out:
borishaifa [10]
<span>This exercise should show you that as h approaches zero you get the value of the derivative of x^2 at x=1.

</span><span>the change in x^2) / h
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lidiya [134]
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dybincka [34]

Answer:

3.50

Step-by-step explanation:

3 0
3 years ago
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