the molecular formula is calculated as follows
find the mole of each molecule
that is for carbon = 26.7/12= 2.23 moles
hydrogen= 2.24/1=2.24 moles
oxygen= 71.1/16=4.44 moles
find the mole ratio of each element
that is divide all moles by the smallest mole( 2.23)
for carbon=2.23/2.23=1,
hydrogen = 2.24/2,23=1
oxygen= 4.44/2.23= 2
the empirical formula = CHO2
therefore the molecular formula=(CHO2)n=270.1
{ ( 12x 1) + 1x1) +(16x2)}n=270.1
45n=270.1
n=6
molecular formula is therefore=(CHO2)6=C6H6O12
Answer:
Ka = 4.76108
Explanation:
- CO(g) + 2H2(g) ↔ CH3OH(g)
∴ Keq = [CH3OH(g)] / [H2(g)]²[CO(g)]
[ ]initial change [ ]eq
CO(g) 0.27 M 0.27 - x 0.27 - x
H2(g) 0.49 M 0.49 - x 0.49 - x
CH3OH(g) 0 0 + x x = 0.11 M
replacing in Ka:
⇒ Ka = ( x ) / (0.49 - x)²(0.27 - x)
⇒ Ka = (0.11) / (0.49 - 0.11)² (0.27 - 0.11)
⇒ Ka = (0.11) / (0.38)²(0.16)
⇒ Ka = 4.76108
The will be c. Covalent bond and
Answer:
Decomposition
Explanation:
A decomposition reaction is when a compound breaks down into simpler substances.
in our case Ammonium hydroxide requires an input of energy to obtain Ammonia gas and water.
