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olga2289 [7]
2 years ago
11

Will a deflated football sink in water?

Chemistry
2 answers:
Tom [10]2 years ago
7 0
No it will float it’s lighter
Leno4ka [110]2 years ago
4 0

Answer:

no

Explanation:

light objects float

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The energy is used to pump hydrogen ions into the thylakoid space
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What is the cation called?
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Explanation:

HYDRONIUM

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Identify one step in the water cycle that is driven by the force of gravity
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i believe its precipitation??

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Which of the following compounds' solubility will not be affected by a low pH in solution?
Whitepunk [10]

The compound solubility which will not be affected by a low pH in solution is AgBr.

<h3>What is pH?</h3>

pH is a measure of the acidity or basicity of any solution and according to the pH scale 0 to 6.9 shows the acidity, 7 is neutral and 7.1 to 14 shows the basicity of any solution.

  • AgBr is sparingly soluble in water and not soluble in acids, so if we low the pH of the solution towards the acidity its solubility not affected.
  • NiCO₃ is a basic salt and and shows solubility in the acidic medium so change in pH will affect its solubility.
  • Co(OH)₂ it is also a basic compound and shows its solubility in the acidic medium and get affected when change in pH takes place.
  • PbF₂ is a strong base and also shows solubility in the acidic medium easily, so get affected when change in pH takes place.
  • In CuS, sulphide is basic ion and whole compound shows solubility in the acidic medium and get affected when low pH of solution takes place.

AgBr is not affected by a low pH in solution.

To know more about solubility, visit the below link:

brainly.com/question/23946616

3 0
2 years ago
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The molarity of a solution prepared by dissolving 4.11 g of NaI in enough water to prepare 312 mL of solution is
Dimas [21]

Answer:

The correct answer is 8.79 × 10⁻² M.

Explanation:

Based on the given information, the mass of NaI given is 4.11 grams. The molecular mass of NaI is 149.89 gram per mole. The moles of NaI can be determined by using the formula,

No. of moles of NaI = Weight of NaI/ Molecular mass

= 4.11 / 149.89

= 0.027420

The vol. of the solution given is 312 ml or 0.312 L

The molarity can be determined by using the formula,

Molarity = No. of moles/ Volume of the solution in L

= 0.027420/0.312

= 0.0879 M or 8.79 × 10⁻² M

6 0
2 years ago
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