Will a deflated football sink in water?

At 700 K, the reaction2SO2(g) + O2(g) 2SO3(g)has the equilibrium constant Kc = 4.3 x 106, and the following concentrations are p

dedylja [7]

Explanation:

The given reaction is as follows.

$2SO_{2} + O_{2}(g) \rightarrow 2SO_{3}(g)$

Value of equilibrium constant is given as $K_{c}$ = 4.3 \times 10^{6}[/tex].

Concentration of given species is $[SO_2]$ = 0.010 M; $[SO_3]$ = 10.M; $[O_2]$ = 0.010 M.

Formula for experimental value of equilibrium constant (Q) is as follows.

Q = $\frac{[SO_{3}]^{2}}{[SO_{2}]^{2}[O_{2}]}$

Putting the given concentration as follows.

Q = $\frac{[SO_{3}]^{2}}{[SO_{2}]^{2}[O_{2}]}$

Q = $\frac{(10)^{2}}{(0.010)^{2}(0.010)}$

Q = $10^{8}$

It is known that when Q > $K_{eq}$ , then reaction moves in the backward direction.

When Q < $K_{eq}$ , then reaction moves in the forward direction.

When Q = $K_{eq}$ , then reaction is at equilibrium.

As, for the given reaction Q > $K_{eq}$ then it means reaction moves in the backward direction.

Thus, we can conclude that the reaction is moving in the backward direction, that is, right to left to reach the equilibrium.

5 0

3 years ago

Select the true statements regarding these resonance structures of formate.? Each carbon-oyxgen bond is somewhere between a sing

son4ous [18]

Answer : Option 1) The true statement is each carbon-oxygen bond is somewhere between a single and double bond and the actual structure of format is an average of the two resonance forms.

Explanation : The actual structure of formate is found to be a resonance hybrid of the two resonating forms. The actual structure for formate do not switches back and forth between two resonance forms.

The O atom in the formate molecule with one bond and three lone pairs, in the resonance form left with reference to the attached image, gets changed into O atom with two bonds and two lone pairs.

Again, the O atom with two bonds and two lone pairs on the resonance form left, changed into O atom with one bond and three lone pairs. It concludes that each carbon-oxygen bond is neither a single bond nor a double bond; each carbon-oxygen bond is somewhere between a single and double bond.

Also, it is seen that each oxygen atom does not have neither a double bond nor a single bond 50% of the time.

7 0

2 years ago

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If you have 12.5g of fluoride and 16.2g of sodium, which is the limiting reactant and how sodium fluoride in grams is your theor

Korvikt [17]

Answer:

F2 is the limiting reactant

27.6 grams of NaF is produced.

Explanation:

Balance the equation first.

2Na+ F2 ---> 2NaF

To find the limiting reactant, solve for how much NaF can be produced with Na and F2

12.5g F2 x (1 mole F2/ 38.00 grams F2)x (2 mole NaF/ 1 mole F2)

=0.658 moles NaF

16.2g Na x (1 mole Na/ 22.99 grams Na)x (2 mole NaF/ 2 mole Na)

=0.705 moles NaF

Since F2 produced the least NaF, F2 is the limiting reactant.

Now, to find how much NaF there is, use the moles solved above with F2 as the limiting reactant.

0.658 moles NaF x (41.99 grams NaF/ 1 mole NaF)= 27.6 moles NaF

27.6 moles of NaF would be theoretically produced.

8 0

3 years ago

Compare 1 mole of H2, 1 mole of O2, and 1 mole of F2. (a) Which has the largest number of molecules? Explain why. (b) Which has

AURORKA [14]

a) Answer:

Number of molecules in 1 mole

Explanation:

a) Whether we take any of the substance among all three of the given substances they will have the same number of molecules in 1 mole of the substance is considered and the value for this will be $6.023 x 10^23$

b) Answer:

In the given question mass of the substance which is greatest is asked for one mole and we also know that mass of one mole is given by molar mass.

Explanation:

b) It is known that $31.98g/mol$ is the molar mass for oxygen which is greater than that of hydrogen while fluorine has a molar mass of $38.0 g/mol$ which on comparison shows that, it is the highest amongst all three.