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IgorC [24]
3 years ago
14

An electrical company charges 15 p per unit of energy (kWh).

Chemistry
1 answer:
Alja [10]3 years ago
4 0

Answer:

180 p

Explanation:

Energy refers to the capacity of doing work.

Amount charged by an electrical company = 15 p per unit of energy (kWh)

As 1 W = 1000 kW,

500W=\frac{500}{1000}kW=0.5\,kW

Also, 1 day = 24 hours.

Cost of running a 500 W freezer = 0.5 kW freezer for 1 hour = 15\times 0.5=7.5\,p

Therefore,

cost of running a 0.5 kW freezer for a day ( 24 hours ) = 7.5\times 24=180\,p

Amount charged by an electrical company = 15 p per unit of energy (kWh)

As 1 W = 1000 kW,

500W=\frac{500}{1000}kW=0.5\,kW

Also, 1 day = 24 hours.

Cost of running a 500 W freezer = 0.5 kW freezer for 1 hour = 15\times 0.5=7.5\,p

Therefore,

cost of running a 0.5 kW freezer for a day ( 24 hours ) = 7.5\times 24=180\,p

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Answer:

Second reaction

NO2 + F -------> NO2F

Rate of reaction:

k1 [NO2] [F2]

Explanation:

NO2 + F2 -----> NO2F + F slow step1

NO2 + F -------> NO2F fast. Step 2

Since the first step is the slowest step, it is the rate determining step of the reaction

Hence:

rate = k1 [NO2] [F2]

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3 years ago
Calcium and water form calcium hydroxide and hydrogen gas also called what type of reaction
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Reaction of calcium with water
Calcium reacts slowly with water. This is in contrast with magnesium, immediately above calcium in the periodic table, which is virtually unreactive with cold water. The reaction forms calcium hydroxide, Ca(OH)2 and hydrogen gas (H2).
4 0
3 years ago
Calculate how many grams of iron can be made from 16.5 grams of iron(III) oxide if hydrogen gas is in excess?
miss Akunina [59]

Taking into account the reaction stoichiometry, 11.54 grams of Fe are formed from 16.5 grams of iron(III) oxide if hydrogen gas is in excess.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Fe₂O₃ + 3 H₂ → 2 Fe + 3 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Fe₂O₃: 1 mole
  • H₂: 3 moles
  • Fe: 2 moles
  • H₂O: 3 moles

The molar mass of the compounds is:

  • Fe₂O₃: 159.7 g/mole
  • H₂: 2 g/mole
  • Fe: 55.85 g/mole
  • H₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Fe₂O₃: 1 mole ×159.7 g/mole= 159.7 grams
  • H₂: 3 moles ×2 g/mole= 6 grams
  • Fe: 2 moles ×55.85 g/mole= 111.7 grams
  • H₂O: 3 moles ×18 g/mole= 54 grams

<h3>Mass of each product formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 159.7 grams of Fe₂O₃ form 111.7 grams of Fe, 16.5 grams of Fe₂O₃ form how much mass of Fe?

mass of Fe=\frac{16.5 grams of Fe_{2} O_{3} x111.7 grams of Fe}{159.7 grams of Fe_{2} O_{3}}

<u><em>mass of Fe= 11.54 grams</em></u>

Then, 11.54 grams of Fe are formed from 16.5 grams of iron(III) oxide if hydrogen gas is in excess.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

7 0
2 years ago
Which compound has the smallest mass. H2O CO H2O2 CO2
wolverine [178]
H2O as it has a relative atomic mass of 18
7 0
3 years ago
Omg pls help i dunno what the frick frack this is
snow_lady [41]

Answer:

1. Mass of KCl produced = 774.8 g of KCl

2. Mass of KNO₃ produced = 13.837g

3. Moles of NaOH made = 0.846 moles

4. Moles of LiCl produced = 0.846 moles

5. Moles of CO₂ produced = 207.6 moles

Explanation:

1. From the equation of reaction, 1 mole of ZnCl₂ produces, 2 moles of KCl.

5.02 moles of ZnCl₂ will produce, 2 × 5.02 moles of KCl = 10.4 moles of KCl

Molar mass of KCl = (39 + 35.5) g/mol = 74.5 g/mol

10.4 moles of KCl = 10.4 × 74.5 g

Mass of KCl produced = 774.8 g of KCl

2. Mole ratio of KNO₃ and KOH = 1:1

O.137 moles of KOH will produce 0.137 moles of KNO₃

Molar mass of KNO₃ = 101 g/mol

Mass of KNO₃ produced = 0.137 × 101 g = 13.837g

3. Molar mas of Ca(OH)₂ = 74.0 g

Moles of Ca(OH)₂ in 31.3 g = 31.3/74.0 = 0.423 moles of Ca(OH)₂

Mole ratio of NaOH and Ca(OH)₂ in the reaction = 2 : 1

Moles of NaOH made = 2 × 0.423 = 0.846 moles

4. Molar mass of MgCl₂ = 95.0 g

Moles of MgCl₂ in 40.2 g = 40.2/95.0 = 0.423 moles

From the reaction equation, mole ratio of MgCl₂ and LiCl = 1:2

Moles of LiCl produced = 2 × 0.423 = 0.846 moles

5. From the equation of reaction, 1 mole of C₆H₁₀O₅ produces 6 moles of cO₂

34.6 moles of C₆H₁₀O₅ will produce 34.6 × 6 moles of CO₂

Moles of CO₂ produced = 207.6 moles

4 0
3 years ago
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