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3 years ago

What is the formula of the ionic compound expected to form between the elements chlorine and aluminum?

Chemistry

1 answer:

galben [10]3 years ago

3 0

Answer: AlCl3

Explanation:

Aluminum is in group 13 and has a valency of 3. Chlorine is in group 17 and has a valency of 1. When a compound is formed, it reflects the valencies of each of the combining elements. This can be simplified by saying that the combining elements exchange their valencies. Cl gets 3 and All gets 1 forming a compound with the formula shown above.

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Consider the unbalanced equation for the oxidation of aluminum.

SashulF [63]

In order to balance an equation, we apply the principle of conservation of mass, which states that mass can neither be created nor destroyed. Therefore, the mass of an element before and after a reaction remains constant. Here, the balanced equation becomes:
4Al + 3O₂ → 2Al₂O₃

The coefficients are 4, 3 and 2.

8 0

2 years ago

Read 2 more answers

In a very violent reaction called a thermite reaction, aluminum metal reacts with iron (III) oxide to form iron metal and alumin

leva [86]

Here's the equation:
Fe2 O3 + 2Al → 2Fe + Al2 O3

Here's the question.
What mass of Al will react with 150g of Fe2 O3?

In every 2 moles Al you need 1 mole Fe2O3 

moles = mass / molar mass 
moles Fe2O3 = 150 g / 159.69 g/mol 
= 0.9393 moles 

moles Al needed = 2 x moles Fe2O3 
= 2 x 0.9393 mol 
= 1.879 moles Al needed 

mass = molar mass x moles 
mass Al = 26.98 g/mol x 1.879 mol 
= 50.69 g 
= 51 g (2 sig figs)

So the mass of Al that will react with 150g of Fe2 O3 is 51 grams.

3 0

3 years ago

The concentrations of the products at equilibrium are [pcl3] = 0.180 m and [cl2] = 0.250 m. what is the concentration of the rea

sineoko [7]

We have Kc = 4.2 x 10^-2 (given but missing in the question)
and When the balanced equation for this reaction is:
PCl5(g) ↔ PCl3(g) + Cl2(g)
so, according to the Kc formula:
Kc = the concentration of products / the concentration of the reactants
so, to get the concentration of the reactants in equilibrium, the concentration of the products / the concentration of the reactants should equal the Kc value which is given in the question (missing in your question).
So by substitution in Kc formula:
Kc = [PCl3]*[Cl2] / [PCl5]
4.2 x 10^-2 = 0.18 * 0.25 /[PCl5]
∴[PCl5] = 0.18*0.25 / 4.2x10^-2 = 1.07
So the concentration of the reactants in equilibrim = 1.07

4 0

3 years ago

Octasulfur reacts with pure oxygen to produce sulfur dioxide. Determine the percent

Margaret [11]

Answer:

Octasulfur is just S8. Eight S atoms in

a sort of crown shape. Sulfur Dioxide is a gas, SO2. Does that help?

Explanation:

5 0

3 years ago

Having done the experiment, explain briefly how the mass of zinc not equal the mass of lead gained (hint: the periodic table)

masya89 [10]

Answer:

Due to the difference in the relative atomic masses and therefore, the molecular masses of Zn and Pb, one mole of Zn is about 3.2 times lighter than one mole of Pb

Explanation:

From the periodic table, we have;

The atomic number of zinc, Zn = 30

The atomic mass of zinc, Zn = 65.38 amu

The molar mass of zinc, Zn = 65.38 g/mol

The atomic number of lead, Pb = 82

The atomic mass of lead, Pb = 207.2 amu

The molar mass of lead, Pb = 207.2 g/mol

Therefore, whereby equal number of moles of Zn is lost and Pb is gained, we have;

Mass of 1 mole of Zn = 65.38 grams

Therefore, 1 gram of Zn = 1/65.38 moles = 0.0153 moles

0.12 grams of Zn = 0.12×0.0153 = 0.00184 moles of Zn

Given that equal number of moles of Zn and Pb are involved in the reaction, the number of moles of Pb gained = 0.00184 moles

The mass of Pb gained = Number of moles of Pb gained × Molar mass of Pb

The mass of Pb gained = 0.00184 × 207.2 = 0.38 g ≈ 0.4 g.

Amount of Pb gained = 0.43 g ≈ 0.4 g

4 0

2 years ago