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2 years ago

11. What is the value of x? A 48 B 30 C 60 D 36

Mathematics

1 answer:

Julli [10]2 years ago

4 0

I believe it’s 36 sorry if it’s incorrect

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What is the answer and how do I solve it?

vichka [17]

The lengths of the rectangles are 7 and 12 respectively. Form the ratio 7/12. The widths of the rects. are x and 5 respectively. Form the ratio x/5. Now equate these two ratios:

7 x
--- = ---
12 5

Solve this for x. One way to do this would be to cross-multiply, obtaining 12x = 35, and solving this result for x. x will be a fraction. Write the numerator and denominator in the boxes given.

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2 years ago

Find the slope of the line that passes through (1,5) and (10, 10).

Oliga [24]

Answer:

$\frac{5}{9}$

Step-by-step explanation:

The formula for the slope with two points given would be

$\frac{y_2-y_1}{x_2-x_1}$

Substitute

$\frac{10-5}{10-1} =\frac{5}{9}$

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3 years ago

What is the following sum? Assume x20 and 20.<br> √√x²y³ +2√√x³y² + xy √√y

max2010maxim [7]

The value of the expression $\sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y$ is $2xy\sqrt{y} + 2xy^2\sqrt{x}$

<h3>How to evaluate the sum?</h3>

The attachment represents the proper format of the question

The summation expression is given as:

$\sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y$

Expand the radicands

$\sqrt{x^2y^2 * y} + 2\sqrt{x^2y^4* x} + xy\sqrt y$

Evaluate the square roots

$xy\sqrt{y} + 2xy^2\sqrt{x} + xy\sqrt y$

Add the like terms

$2xy\sqrt{y} + 2xy^2\sqrt{x}$

Hence, the value of the expression $\sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y$ is $2xy\sqrt{y} + 2xy^2\sqrt{x}$

Read more about expressions at:

brainly.com/question/723406

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1 year ago

Evaluate (x+y)^0 for x=4 and y=3

daser333 [38]

Anything to the zeroth power is 1, so the answer is just 1.

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2 years ago

Read 2 more answers

George’s parents are saving for his college fund. they put $5,000 into an interest bearing account with a compound interest rate

sergey [27]

so hmmm is compound interest, now, we'll be assuming the compounding period is per year, or annually, so it happens once per year.

$~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 5.5\%\to \frac{5.5}{100}\dotfill &0.055\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &15 \end{cases} \\\\\\ A=5000\left(1+\frac{0.055}{1}\right)^{1\cdot 15}\implies A=5000(1.055)^{15}$

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2 years ago