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3 years ago

18. When objects come into contact with each other they will eventually reach the same temperature. This is called ________ .

1 answer:

8 0

Heat Flow. The heat is transferred from the hotter object to the cooler object. The heat transfer happens until they come to a thermal equailibrium and the temperatures are the same. Heat usually always flows froma object towards the cool object.

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An AC generator supplies 230 V peak voltage at 210 Hz frequency. How much power is dissipated in a resistor with R = 225 Ω resis

sesenic [268]

Answer:

The power dissipated in a resistor is 117.54 watts.

Explanation:

Given that,

Peak voltage of the Ac generator, V = 230 V

Frequency, f = 210 Hz

Resistance, R = 225 ohms

We need to find the power dissipated in a resistor. The power generated is given by :

$P=\dfrac{V^2_{rms}}{R}$

$V_{rms}=\dfrac{V}{\sqrt{2} }\\\\V_{rms}=\dfrac{230}{\sqrt{2} } \\\\V_{rms}=162.63\ V$

So,

$P=\dfrac{162.63^2}{225}\\\\P=117.54\ W$

So, the power dissipated in a resistor is 117.54 watts. Hence, this is the required solution.

7 0

4 years ago

A plane fillies along a straight line path after taking off and it ends up 220 km farther east and 110km farther north relative

DENIUS [597]

330km hope this helped you.

3 0

3 years ago

The moon Phobos orbits Mars

shepuryov [24]

$27.9816 \times 10^{3} s$ is the period of orbit.

<u>Explanation: </u>

The equation that is useful in describing satellites motion is Newton form after Kepler's Third Law. The period of the satellite (T) and the average distance to the central body (R) are related as the following equation:

$\frac{T^{2}}{R^{3}}=\frac{4 \times \pi^{2}}{G \times M_{c e n t r a l}}$

Where,

T is the period of the orbit

R is the average radius of orbit

G is gravitational constant $6.673 \times 10^{-11} \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{kg}^{2}$

Here, given data

$M=6.23 \times 10^{23} \mathrm{kg}$

$R=9.38 \times 10^{6} \mathrm{m}$

Substitute the given values, we get T as

$\frac{T^{2}}{\left(9.38 \times 10^{6}\right)^{3}}=\frac{4 \times(3.14)^{2}}{\left(6.673 \times 10^{-11}\right) \times 6.23 \times 10^{23}}$

$T^{2}=\frac{4 \times 9.8596 \times 825.29 \times 10^{18}}{41.57 \times 10^{12}}$

$T^{2}=\frac{32548.12 \times 10^{18-12}}{41.57}=782.97 \times 10^{6}$

Taking square root, we get

$T=27.9816 \times 10^{3} s$

4 0

3 years ago

The bands on Jupiter are ultimately caused by...

Margaret [11]

Precision because it’s the answer

7 0

3 years ago

When a red giant dies, before it becomes a WHITE DWARF (small, dim, hot star) that eventually becomes a BLACK DWARF (remnant, da

vagabundo [1.1K]

some massive black dwarfs may eventually produce <u>supernova explosions. </u>These will occur if pycnonuclear (density-based) fusion processes much of the star to iron, which would lower the Chandrasekhar limit for some black dwarfs below their actual mass.

6 0

3 years ago