An airplane is flying horizontally with a constant momentum during a time interval ?t. (a) Is there a net impulse acting on the
1 answer:
Answer:
Explanation:
Given
Airplane is flying with horizontally with a constant momentum during time interval
Impulse is given by change in momentum, so there is no net impulse on the Plane because momentum is constant
(b) As there is no change in momentum therefore impulse of thrust and air drag is balanced i.e. both are equal in magnitude but act in opposite direction
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Answer:
rev/s
Explanation:
= mass attached to each hand = 5 kg
= initial distance of masses in each hand = 1 m
= final distance of masses in each hand = 0.1 m
= moment of inertia of body = 5 kgm²
= initial total moment of inertia =
= initial angular velocity = 1 rev/s
= final total moment of inertia =
= final angular velocity = ?
Using conservation of angular momentum
rev/s
Answer:
<em>D. The total force on the particle with charge q is perpendicular to the bottom of the triangle.</em>
Explanation:
The image is shown below.
The force on the particle with charge q due to each charge Q =
we designate this force as N
Since the charges form an equilateral triangle, then, the forces due to each particle with charge Q on the particle with charge q act at an angle of 60° below the horizontal x-axis.
Resolving the forces on the particle, we have
for the x-component
= N cosine 60° + (-N cosine 60°) = 0
for the y-component
= -f sine 60° + (-f sine 60) = -2N sine 60° = -2N(0.866) = -1.732N
The above indicates that there is no resultant force in the x-axis, since it is equal to zero ( = 0).
The total force is seen to act only in the y-axis, since it only has a y-component equivalent to 1.732 times the force due to each of the Q particles on q.
<em>The total force on the particle with charge q is therefore perpendicular to the bottom of the triangle.</em>
