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Nataly [62]
3 years ago
15

An airplane is flying horizontally with a constant momentum during a time interval ?t. (a) Is there a net impulse acting on the

plane during this time? Use the impulse-momentum theorem to guide your thinking. (b) In the horizontal direction, both the thrust generated by the engines and air resistance act on the plane. Considering your answer to part (a), how is the impulse of the thrust related in magnitude and direction to the impulse of the force due to the air resistance?
Physics
1 answer:
goldenfox [79]3 years ago
7 0

Answer:

Explanation:

Given

Airplane is flying with horizontally with a constant momentum during time interval \Delta t

Impulse is given by change in momentum, so there is no net impulse on the Plane because momentum is constant

(b) As there is no change in momentum therefore impulse of thrust and air drag is balanced i.e. both are equal in magnitude but act in opposite direction                            

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Terrestrial coordinates expanded into infinite space onto a celestial sphere is called the
Vinvika [58]

Answer:

The correct option is;

C) Equatorial coordinate system

Explanation:

The equatorial coordinate system is which has the most wide spread use in coordinate system for astronomy for mapping the location of celestial bodies such as stars by use of an imaginary projected celestial sphere or to rectangular coordinates with the Earth at the center.  Extending the Earth's axis onto the celestial sphere is essentially the projection of the Earths axis outwards to intersect the sphere at the celestial poles.

7 0
3 years ago
Point charges q1=50μCq1=50μC and q2=−25μCq2=−25μC are placed 1.0 m apart. (a) What is the electric field at a point midway betwe
avanturin [10]

Answer:

a) E = 2.7x10⁶ N/C

b) F = 54 N

Explanation:

a) The electric field can be calculated as follows:

E = \frac{Kq}{d^{2}}

<u>Where</u>:

K: is the Coulomb's constant = 9x10⁹ N*m²/C²

q: is the charge

d: is the distance

Now, we need to find the electric field due to charge 1:

E_{1} = \frac{9 \cdot 10^{9} N*m^{2}/C^{2}*50 \cdot 10^{-6} C}{(0.5 m)^{2}} = 1.8 \cdot 10^{6} N/C

The electric field due to charge 2 is:

E_{2} = \frac{9 \cdot 10^{9} N*m^{2}/C^{2}*(-25) \cdot 10^{-6} C}{(0.5 m)^{2}} = -9.0 \cdot 10^{5} N/C

The electric field at a point midway between them is given by the sum of E₁ and E₂ (they are in the same direction, that is to say, to the right side):

E_{T} = E_{1} + E_{2} = 1.8 \cdot 10^{6} N/C + 9.0 \cdot 10^{5} N/C = 2.7 \cdot 10^{6} N/C to the right side                                                                                                

Hence, the electric field at a point midway between them is 2.7x10⁶ N/C to the right side.  

b) The force on a charge q₃ situated there is given by:

E_{T} = \frac{F_{T}}{q_{3}} \rightarrow F_{T} = E_{T}*q_{3}

F = 2.7 \cdot 10^{6} N/C*20 \cdot 10^{-6} C = 54 N

Therefore, the force on a charge q₃ situated there is 54 N.  

I hope it helps you!

3 0
3 years ago
Two waves with an amplitude of 54 units and 64 units arrive at a point in a medium simultaneously. If the two waves are in phase
igomit [66]
The amplitude of the wave is equal to the sum of the amplitudes of the two waves if the phase of the two waves is the same.
54+64=118 <span>units

</span>
3 0
3 years ago
a 40 kg-skier starts at the top of a 12-metter high slope. at the bottom she is travling 10 m/s. how much energy dose she lose t
jekas [21]
Potential energy at the top = (mass) x (gravity) x (height)

                                           = (40 kg) x (9.8 m/s²) x (12 m)

                                           =            4,704 Joules


Kinetic energy at the bottom = 1/2 (mass) x (speed)²

                                              =  1/2 (40 kg) x (10 m/s)²

                                              =        2,000 Joules .


Energy lost between the top and the bottom
  
                                   (4,704 joules) - (2,000 joules)

                               =            2,704 Joules
3 0
4 years ago
Sasha lifts a couch 8.2 meters from the ground floor of her house to the attic. If the couch has a mass of 120 kg, what is the g
gavmur [86]

As we know that gravitational potential energy is given by

U = mgH

here we have

m = mass = 120 kg

g = 9.81 m/s^2

h = height = 8.2 m

now from above formula

U = 120kg (9.81 m/s^2) (8.2 m)

U = 9653.04 J

so above is the gravitational potential energy of the couch

4 0
3 years ago
Read 2 more answers
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