1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Reika [66]
3 years ago
9

An AC generator supplies 230 V peak voltage at 210 Hz frequency. How much power is dissipated in a resistor with R = 225 Ω resis

tance connected to the generator?
Physics
1 answer:
sesenic [268]3 years ago
7 0

Answer:

The power dissipated in a resistor is 117.54 watts.

Explanation:

Given that,

Peak voltage of the Ac generator, V = 230 V

Frequency, f = 210 Hz

Resistance, R = 225 ohms

We need to find the power dissipated in a resistor. The power generated is given by :

P=\dfrac{V^2_{rms}}{R}

V_{rms}=\dfrac{V}{\sqrt{2} }\\\\V_{rms}=\dfrac{230}{\sqrt{2} } \\\\V_{rms}=162.63\ V

So,

P=\dfrac{162.63^2}{225}\\\\P=117.54\ W

So, the power dissipated in a resistor is 117.54 watts. Hence, this is the required solution.

You might be interested in
A satellite is to be launched into an orbit of radius,r Show that v = 2gr, where V is the
Snezhnost [94]

Explanation:

We start by using the conservation law of energy:

\Delta{K} + \Delta{U} = 0

or

\dfrac{1}{2}mv^2 - G\dfrac{mM}{r} = 0

Simplifying the above equation, we get

v^2 = 2G\dfrac{M}{r}

We can rewrite this as

v^2 = 2\left(G\dfrac{M}{r^2}\right)r

Note that the expression inside the parenthesis is simply the acceleration due to gravity g so we can write

v^2 = 2gr

where v is the launch velocity.

6 0
3 years ago
Most of the stars in the Milky Way will end their lives as
umka21 [38]
<span> </span>Most of the stars in the Milky Way will end their lives as white dwarfs
4 0
3 years ago
Read 2 more answers
Tennis balls traveling at greater than 100 mph routinely bounce off tennis rackets. At some sufficiently high speed, however, th
Kipish [7]

Answer:

Probability of tunneling is 10^{- 1.17\times 10^{32}}

Solution:

As per the question:

Velocity of the tennis ball, v = 120 mph = 54 m/s

Mass of the tennis ball, m = 100 g = 0.1 kg

Thickness of the tennis ball, t = 2.0 mm = 2.0\times 10^{- 3}\ m

Max velocity of the tennis ball, v_{m} = 200\ mph = 89 m/s

Now,

The maximum kinetic energy of the tennis ball is given by:

KE = \frac{1}{2}mv_{m}^{2} = \frac{1}{2}\times 0.1\times 89^{2} = 396.05\ J

Kinetic energy of the tennis ball, KE' = \frac{1}{2}mv^{2} = 0.5\times 0.1\times 54^{2} = 154.8\ m/s

Now, the distance the ball can penetrate to is given by:

\eta = \frac{\bar{h}}{\sqrt{2m(KE - KE')}}

\bar{h} = \frac{h}{2\pi} = \frac{6.626\times 10^{- 34}}{2\pi} = 1.0545\times 10^{- 34}\ Js

Thus

\eta = \frac{1.0545\times 10^{- 34}}{\sqrt{2\times 0.1(396.05 - 154.8)}}

\eta = \frac{1.0545\times 10^{- 34}}{\sqrt{2\times 0.1(396.05 - 154.8)}}

\eta = 1.52\times 10^{-35}\ m

Now,

We can calculate the tunneling probability as:

P(t) = e^{\frac{- 2t}{\eta}}

P(t) = e^{\frac{- 2\times 2.0\times 10^{- 3}}{1.52\times 10^{-35}}} = e^{-2.63\times 10^{32}}

P(t) = e^{-2.63\times 10^{32}}

Taking log on both the sides:

logP(t) = -2.63\times 10^{32} loge

P(t) = 10^{- 1.17\times 10^{32}}

6 0
3 years ago
A positively charged particle is in the center of a parallel-plate capacitor that has charge ±Q on its plates. SUppose the dista
slamgirl [31]

Answer:

Stay the same

Explanation:

First of all, let's find how the capacitance of the capacitor changes.

Initially, it is given by

C=\frac{\epsilon_0 A}{d}

where

\epsilon_0 is the vacuum permittivity

A is the area of the plates

d is the separation between the plates

From the formula, we see that the capacitance is inversely proportional to the separation between the plates. In this problem, the distance between the plates is doubled, so the capacitance will be halved:

C' = \frac{1}{2}C

The potential difference across the capacitor is given by

V= \frac{Q}{C}

where

Q is the charge on the plates

C is the capacitance

We see that the voltage is inversely proportional to the capacitance. We said that the capacitance has halved: therefore, the potential difference across the two plates will double:

V' = 2 V

Now we can analyze the electric field between the plates of the capacitor, which is given by

E=\frac{V}{d}

we said that:

- The voltage has doubled: V' = 2 V

- The distance between the plates has doubled: d' = 2 d

therefore, the new electric field will be

E'=\frac{2V}{2d}=\frac{V}{d}=E

So, the electric field is unchanged. And since the force on the particle at the center is directly proportional to the electric field:

F = qE

Then the force on the particle will stay the same.

4 0
3 years ago
50 points please help ASAP! !
Contact [7]

Answer:

The sum of the initial and final velocity is divided by 2 to find the average. The average velocity calculator uses the formula that shows the average velocity (v) equals the sum of the final velocity (v) and the initial velocity (u), divided by 2.

4 0
3 years ago
Other questions:
  • What is the surface temperature of a distant star having a peak wavelength of 475 nm?
    13·1 answer
  • A ball is thrown downward from the top of a 55.0 m tower with an initial speed of 11.0 m/s. Assuming negligible air resistance,
    14·1 answer
  • A second-class lever will always multiply distance.<br> a. true<br> b. false
    11·1 answer
  • In Science class, a student has been given a small ball that has a string attached to it
    12·1 answer
  • A 400-kg space probe has a weight of 3,560 N on one of the above planets. According to the table
    7·1 answer
  • Please answer please answer please answer
    12·2 answers
  • An insulated rigid tank initially contains 1.4-kg saturated liquid water and water vapor at 200°C. At this state, 25 percent of
    9·1 answer
  • Identify 3 preys and their preys
    13·1 answer
  • Which one is it? Chemical, or ,Mechanical<br><br><br> Flakes of brick fall off due to wind and rain.
    5·2 answers
  • Hello people ~
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!