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Eva8 [605]
3 years ago
6

3(2x^2+5)-12 for x is 3

Mathematics
1 answer:
dedylja [7]3 years ago
5 0

3(2x^2+5)-12

3(2x^2)= 6x^2

3(5) = 15

6x^2+15-12

6x^2+3

Plug in the x

6(3)^2+3

Exponent first so 3^2 is 9

6(9)+3

54+3

57 is the answer.

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The expression −8x3(7x6 − 3x5) is equivalent to?
Mama L [17]

Answer:

-56x^9+24x^8

Step-by-step explanation:

3 0
4 years ago
Pre cal/cal master needed
weqwewe [10]
Take x-2 and insert it into 2x^2 + 3x-2 where the x is located 
2x^2 + 3x-2
2(x-2)^2 + 3(x-2)-2

Now work out 2(x-2)^2 + 3(x-2)-2 also follow PEMDAS
2(x-2)^2 + 3(x-2)-2 
Since (x-2)^2 is an Exponent, lets work with that first and expand (x-2)^2.
(x-2)^2
(x -2)(x-2)
x^2 -4x + 4
Now Multiply that by 2 because we have that in 2(x-2)^2
(x-2)^2  =  x^2 -4x + 4
2(x-2)^2  =  2(x^2 -4x + 4)
2(x^2 -4x + 4) = 2x^2 - 8x + 8
2x^2 - 8x + 8

Now that 2(x-2)^2 is done lets move on to 3(x-2).

Use the distributive property and distribute the 3
3(x-2) = 3x - 6

All that is left is the -2 

Now lets put it all together 
2(x-2)^2 + 3(x-2)-2

2x^2 - 8x + 8 + 3x - 6 - 2

Now combine all our like terms 
2x^2 - 8x + 8 + 3x - 6 - 2
Combine:  2x^2      =  2x^2 
Combine: -8x + 3x  =  -5x
Combine:  8 - 6 - 2 =   0

So all we have left is
2x^2 - 5x





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3 years ago
What is the equation of the line that passes through the point (4, 12) and has a y-intercept of -2?
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Answer:

The answer is D.

Step-by-step explanation:

:DDDDDDDDD

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