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Sphinxa [80]
2 years ago
13

Solve for x!!!!!!!!!

Mathematics
1 answer:
Diano4ka-milaya [45]2 years ago
7 0

Answer:

39+32+x=90

71+x=90

x=90-71

x=31

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Algorithms 32.5° + 16°=
Nady [450]
32.5* +16* =48.5*


Hopes it's help
7 0
3 years ago
Please help this is a test I need help quick
RoseWind [281]

Answer:

Parallel is 3

Perpendicular is - 1/3

Step-by-step explanation:

Good luck!

8 0
3 years ago
How do I write this fraction as a decimal 14 3/5
Softa [21]

we have

14 \frac{3}{5}

This is a mixed number

we know that

A mixed number is a combination of a whole number and a fraction.

So

14 \frac{3}{5} is equal to

14 +\frac{3}{5}

where

14 is the whole number

\frac{3}{5} is the fraction

\frac{3}{5}=0.60

14 +\frac{3}{5} =14+0.60\\ \\ =14.60

therefore

the answer is

14.60

3 0
2 years ago
Read 2 more answers
"You measure 34 dogs' weights, and find they have a mean weight of 67 ounces. Assume the population standard deviation is 13.5 o
liraira [26]

Answer:

The 95% confidence interval for the true population mean dog weight is between 62.46 ounces and 71.54 ounces.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96*\frac{13.5}{\sqrt{34}} = 4.54

The lower end of the interval is the sample mean subtracted by M. So it is 67 - 4.54 = 62.46 ounches.

The upper end of the interval is the sample mean added to M. So it is 67 + 4.54 = 71.54 ounces.

The 95% confidence interval for the true population mean dog weight is between 62.46 ounces and 71.54 ounces.

7 0
3 years ago
Solve using the elimination method <br> 0.3x-0.2y=4<br> 0.2x+0.5y=-21/23
Aneli [31]
Do this and then simplify the result

5 0
3 years ago
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