Here's the formula for mechanical advantage.
It's very important, and you should memorize it:
Mechanical Advantage = (output force) divided by (input force) .
#1). Force that moves the object = output force = 550N
Force that it takes = input force = 200N
Use the formula:
(output force) divided by (input force) = 550N/200N = 2.75 .
#2).
#3).
#4).
#5).
#6).
#7).
#8).
#9).
#10).
All of the rest of the problems on the page tell you the input force
and the output force. They can be solved by using the same formula
to calculate the mechanical advantage, just like I did in #1).
I disagree with the first sentence of #11. But by the time you get there,
you'll be an expert in mechanical advantage, so you can investigate and
decide who's correct ... the sheet or me.
Answer:
Explanation:
Given the magnitude of the forces, 7N and 2N, the minimum combining force acting on the forces are when the force's is acting in opposite direction.
Magnitude of the force in opposite direction is 7N - 5N = 2N
The maximum combining force occurs when they act in the same direction. Magnitude of the force in the same direction is 5N+7N = 12N
Hence the range of magnitude requires is 2N≤F≤12N
Answer:
the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms
Explanation:
Given the data in the question;
first we determine the rotational latency
Rotational latency = 60/(3600×2) = 0.008333 s = 8.33 ms
To get the longest time, lets assume the sector will be found at the last track.
hence we will access all the track, meaning that 127 transitions will be done;
so the track changing time = 127 × 15 = 1905 ms
also, we will look for the sectors, for every track rotations that will be done;
128 × 8.33 = 1066.24 ms
∴The Total Time = 1066.24 ms + 1905 ms
Total Time = 2971.24 ms
Therefore, the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms
<u>Answer:</u>
The acceleration of the plane and the time required to reach this speed is (a)= 7.5 
and time(t) = 20 seconds
<u>Explanation:
</u>
Given data Initial velocity 
= 0
Final velocity (
) = 150 m/second
Distance (d) = 1500 m
We have the formula, 
which gives 
= 0+2a(1500)
22500 = 3000 a
acceleration (a) = 7.5 
150 = 7.5 t
t= 150/7.5 = 20
t = 20 seconds.
To solve this problem it is necessary to apply the concepts related to Hooke's Law as well as Newton's second law.
By definition we know that Newton's second law is defined as
m = mass
a = Acceleration
By Hooke's law force is described as
Here,
k = Gravitational constant
x = Displacement
To develop this problem it is necessary to consider the two cases that give us concerning the elongation of the body.
The force to keep in balance must be preserved, so the force by the weight stipulated in Newton's second law and the force by Hooke's elongation are equal, so
So for state 1 we have that with 0.2kg there is an elongation of 9.5cm
For state 2 we have that with 1Kg there is an elongation of 12cm
We have two equations with two unknowns therefore solving for both,
In this way converting the units,
Therefore the spring constant is 313.6N/m
