Question

A 148 g ball is dropped from a tree 11.0 m above the ground. With what speed would it hit the ground

Answer 1

Answer:

14.68m/s

Explanation:

As per the question, the data provided is as follows

Mass = M = 0.148 kg

Height = h = 11 m

Initial velocity = U = 0 m/s

Final velocity = V

Gravitational force = F

Mass = M

Based on the above information, the speed that hit to the ground is

As we know that

Work to be done = Change in kinetic energy

$F ( S) = (\frac{1}{2} ) M ( V^2 - U^2 )$

$M g h = (\frac{1}{2} ) M ( V^2 - U^2 )$

$g h = (\frac{1}{2} ) ( V^2 - U^2 )$

$V^2 - U^2 = 2gh$

$V^2 - 0 = 2gh$

$V = \sqrt{2 g h}$

$= \sqrt{2\times9.8\times11}$

= 14.68m/s